// Numbas version: exam_results_page_options {"name": "Exact values for csc, sec, cot (acute, degrees)", "extensions": [], "custom_part_types": [], "resources": [["question-resources/exact_values.svg", "/srv/numbas/media/question-resources/exact_values.svg"]], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"rulesets": {}, "variable_groups": [], "question_groups": [{"pickingStrategy": "all-ordered", "questions": [], "name": "", "pickQuestions": 0}], "tags": [], "name": "Exact values for csc, sec, cot (acute, degrees)", "functions": {}, "metadata": {"licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International", "description": "

multiple choice testing csc, sec, cot of random(30, 45, 60) degrees

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$2$

", "

$\\sqrt{2}$

", "

$\\dfrac{2}{\\sqrt{3}}$

", "

$\\sqrt{3}$

", "

$\\dfrac{1}{\\sqrt{3}}$

", "

$1$

"], "type": "1_n_2", "prompt": "

The exact value of $\\csc(\\var{theta}^\\circ)$ is

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$2$

", "

$\\sqrt{2}$

", "

$\\dfrac{2}{\\sqrt{3}}$

", "

$\\sqrt{3}$

", "

$\\dfrac{1}{\\sqrt{3}}$

", "

$1$

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The exact value of $\\sec(\\var{theta}^\\circ)$ is

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$2$

", "

$\\sqrt{2}$

", "

$\\dfrac{2}{\\sqrt{3}}$

", "

$\\sqrt{3}$

", "

$\\dfrac{1}{\\sqrt{3}}$

", "

$1$

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The exact value of $\\cot(\\var{theta}^\\circ)$ is

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Recall that $\\csc\\theta=\\dfrac{1}{\\sin\\theta}$, $\\sec\\theta=\\dfrac{1}{\\cos\\theta}$, and $\\cot\\theta=\\dfrac{1}{\\tan\\theta}$.

\n

\n

By drawing the following triangles we can determine the exact values of $\\sin$, $\\cos$ and $\\tan$ (and their reciprocals $\\csc$, $\\sec$, $\\cot$) for the angles $30^\\circ$, $45^\\circ$ and $60^\\circ$.

\n


\n

Alternatively, one can memorise the following table: 

\n

\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
$30^\\circ$$45^\\circ$$60^\\circ$
 
$\\sin$$\\dfrac{1}{2}$$\\dfrac{1}{\\sqrt{2}}$$\\dfrac{\\sqrt{3}}{2}$
 
$\\cos$$\\dfrac{\\sqrt{3}}{2}$$\\dfrac{1}{\\sqrt{2}}$$\\dfrac{1}{2}$
 
$\\tan$$\\dfrac{1}{\\sqrt{3}}$$1$$\\sqrt{3}$
", "statement": "

Often we prefer to work with exact values rather than approximations from a calculator.

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