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$\\dfrac{1}{2}$

", "

$\\dfrac{1}{\\sqrt{2}}$

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$\\dfrac{\\sqrt{3}}{2}$

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$\\dfrac{1}{\\sqrt{3}}$

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$\\sqrt{3}$

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$1$

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The exact value of $\\sin\\Large($$\\var{distheta}\\Large)$ is

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$\\dfrac{1}{2}$

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$\\dfrac{1}{\\sqrt{2}}$

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$\\dfrac{\\sqrt{3}}{2}$

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$\\dfrac{1}{\\sqrt{3}}$

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$\\sqrt{3}$

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$1$

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The exact value of $\\cos\\Large($$\\var{distheta}\\Large)$ is

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$\\dfrac{1}{2}$

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$\\dfrac{1}{\\sqrt{2}}$

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$\\dfrac{\\sqrt{3}}{2}$

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$\\dfrac{1}{\\sqrt{3}}$

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$\\sqrt{3}$

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$1$

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The exact value of $\\tan\\Large($$\\var{distheta}\\Large)$ is

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'\\$\\\\frac{\\pi}{6}\\$'

", "definition": "if(theta=30,'\\$\\\\dfrac{\\\\pi}{6}\\$',if(theta=45,'\\$\\\\dfrac{\\\\pi}{4}\\$','\\$\\\\dfrac{\\\\pi}{3}\\$'))", "name": "distheta", "templateType": "anything"}, "theta": {"group": "Ungrouped variables", "description": "", "definition": "random(30,45,60)", "name": "theta", "templateType": "anything"}}, "functions": {}, "preamble": {"css": "", "js": ""}, "metadata": {"licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International", "description": "

multiple choice testing sin, cos, tan of  random(pi/6, pi/4, pi/3) radians

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Often we prefer to work with exact values rather than approximations from a calculator.

", "advice": "

By drawing the following triangles we can determine the exact values of $\\sin$, $\\cos$ and $\\tan$ (and their reciprocals $\\csc$, $\\sec$, $\\cot$) for the angles $\\dfrac{\\pi}{6}$, $\\dfrac{\\pi}{4}$ and $\\dfrac{\\pi}{3}$.

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Alternatively, one can memorise the following table: 

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\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
$\\dfrac{\\pi}{6}$$\\dfrac{\\pi}{4}$$\\dfrac{\\pi}{3}$
 
$\\sin$$\\dfrac{1}{2}$$\\dfrac{1}{\\sqrt{2}}$$\\dfrac{\\sqrt{3}}{2}$
 
$\\cos$$\\dfrac{\\sqrt{3}}{2}$$\\dfrac{1}{\\sqrt{2}}$$\\dfrac{1}{2}$
 
$\\tan$$\\dfrac{1}{\\sqrt{3}}$$1$$\\sqrt{3}$
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