// Numbas version: exam_results_page_options {"name": "Probabilities from a normal distribution - Electrician", "extensions": ["stats"], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"parts": [{"scripts": {}, "showFeedbackIcon": true, "marks": 0, "gaps": [{"correctAnswerFraction": false, "minValue": "prob2-tol", "variableReplacements": [], "showCorrectAnswer": true, "type": "numberentry", "showFeedbackIcon": true, "maxValue": "prob2+tol", "allowFractions": false, "marks": "4", "notationStyles": ["plain", "en", "si-en"], "variableReplacementStrategy": "originalfirst", "scripts": {}, "correctAnswerStyle": "plain"}], "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "prompt": "

If one electrician is chosen at random, what is probability that this electrician earns over €{upper}? 

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Probability = [[0]](to 2  decimal places)

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If one electrician is chosen at random, what is probability that this electrician earns less than €{lower} ?

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Probability = [[0]](to 2  decimal places)

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If one electrician is chosen at random, what is probability that this electrician earns between €{lower} and €{upper}?

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Probability = [[0]](to 2  decimal places)

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1. Converting to $\\operatorname{N}(0,1)$

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$\\simplify[all,!collectNumbers]{P(X > {upper}) = P(Z > ({upper} -{m}) / {s})} = P(Z>\\var{zupper}) = 1-P(Z<\\var{zupper})=1-\\var{p1} = \\var{prob2}$ to 2 decimal places.

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2.

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$\\simplify[all,!collectNumbers]{P({lower} < X < {upper}) = P(X < {upper})-P(X < {lower})}=P(Z<\\var{zupper})-P(Z<-\\var{zlower}) =\\var{p1}-\\var{p2} = \\var{prob3}$ to 2 decimal places.

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Given a random variable $X$  normally distributed as $\\operatorname{N}(m,\\sigma^2)$ find probabilities $P(X \\gt a),\\; a \\gt m;\\;\\;P(X \\lt b),\\;b \\lt m$.

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rebelmaths

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The salary of an irish electrician is normally distributed with mean €{m} and standard deviation €{s}.

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