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Based on the definition of logarithms determine the following:

", "name": "Logs: scalar multiple to power inside", "parts": [{"marks": 0, "customMarkingAlgorithm": "", "steps": [{"marks": 0, "customMarkingAlgorithm": "", "scripts": {}, "extendBaseMarkingAlgorithm": true, "customName": "", "variableReplacementStrategy": "originalfirst", "showCorrectAnswer": true, "showFeedbackIcon": true, "type": "information", "prompt": "

Here we are using the following log law

\n

\\[\\log_b(a^n)=n\\log_b(a).\\]

\n

Notice how exponentiation on the inside of the log became multiplication on the outside.

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Suppose $\\log_b\\left(a\\right)=\\var{c}$. Evaluate $\\log_b\\left(a^\\var{power}\\right)$ = [[0]].

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Here we are using the following log law

\n

\\[\\log_b(a^n)=n\\log_b(a).\\]

\n

Notice how exponentiation on the inside of the log became multiplication on the outside.

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$\\var{mult}\\log_b\\left(a\\right)$ is equivalent to $\\log_b\\large($[[0]]$\\large)$.

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Here we are using the following log law

\n

\\[\\log_b(a^n)=n\\log_b(a).\\]

\n

Notice how exponentiation on the inside of the log became multiplication on the outside.

\n

\n

But we are also using that

\n

\\[x^{1/n}=\\sqrt[n]{x}.\\]

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Suppose $\\log_b\\left(x\\right)=\\var{d}$. Evaluate $\\log_b\\left(\\sqrt[\\var{root}]{x}\\right)$ = [[0]].

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Here we are using the following log law

\n

\\[\\log_b(a^n)=n\\log_b(a).\\]

\n

Notice how exponentiation on the inside of the log became multiplication on the outside.

\n

\n

But we are also using that

\n

\\[x^{1/n}=\\sqrt[n]{x}.\\]

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$\\frac{1}{2}\\log_b\\left(\\var{square}\\right)$ is equivalent to $\\log_b\\large($[[0]]$\\large)$.

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