// Numbas version: exam_results_page_options
{"name": "Vicky's copy of Rearranging concentration formula for volume (numeric)", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"statement": "", "metadata": {"description": "", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International", "notes": "%w/v is annoying
https://en.wikipedia.org/wiki/Mass_concentration_(chemistry)#Usage_in_biology
"}, "variablesTest": {"condition": "", "maxRuns": 100}, "question_groups": [{"pickQuestions": 0, "pickingStrategy": "all-ordered", "name": "", "questions": []}], "name": "Vicky's copy of Rearranging concentration formula for volume (numeric)", "variable_groups": [{"variables": [], "name": "b"}, {"variables": ["ansb", "millb", "gramsb", "k"], "name": "whole numbers that result in simple decimal"}], "parts": [{"prompt": "A solution is made so it has a percentage concentration of {ansb} % w/v of {chem} by using {gramsb} grams of {chem}. This means that [[0]] mL of solvent was used.
", "stepsPenalty": "1", "scripts": {}, "variableReplacementStrategy": "originalfirst", "variableReplacements": [], "gaps": [{"variableReplacements": [], "scripts": {}, "variableReplacementStrategy": "originalfirst", "minValue": "millb", "correctAnswerFraction": false, "showPrecisionHint": false, "marks": 1, "maxValue": "millb", "type": "numberentry", "showCorrectAnswer": true, "allowFractions": false}], "marks": 0, "steps": [{"prompt": "Given \\[\\text{percentage concentration (w/v)}=\\dfrac{\\text{mass of solute (g)}}{\\text{volume of solvent (mL)}}\\times \\text{100},\\]
\nwe can substitute our values for percentage concentration and mass of solute and rearrange to get the value of 'volume of solvent (mL)'.
\n\n\n\n| $\\text{percentage concentration (w/v)}$ | \n$=$ | \n$\\dfrac{\\text{mass of solute (g)}}{\\text{volume of solvent (mL)}}\\times 100$ | \n
\n\n | \n | \n | \n
\n\n| $\\var{ansb} \\text{ (% w/v)}$ | \n$=$ | \n $\\dfrac{\\var{gramsb}\\text{ (g)}}{\\text{volume of solvent (mL)}}\\times 100$ | \n
\n\n | \n | \n | \n
\n\n| $\\var{ansb} \\text{ % (w/v)}\\times \\text{volume of solvent (mL)}$ | \n$=$ | \n$\\dfrac{\\var{gramsb}\\text{ (g)}}{\\text{volume of solvent (mL)}}\\times 100\\times \\text{volume of solvent (mL)}$ | \n
\n\n| | \n | \n | \n
\n\n| $\\var{ansb} \\text{ % (w/v)}\\times \\text{volume of solvent (mL)}$ | \n$=$ | \n$\\var{gramsb}\\text{ (g)}\\times 100$ | \n
\n\n| | \n | \n | \n
\n\n| $\\dfrac{\\var{ansb} \\text{ % (w/v)}\\times \\text{volume of solvent (mL)}}{\\var{ansb} \\text{ % (w/v)}}$ | \n$=$ | \n$\\dfrac{\\var{gramsb}\\text{ (g)}\\times 100}{\\var{ansb} \\text{ % (w/v)}}$ | \n
\n\n| | \n | \n | \n
\n\n| $\\text{volume of solvent (mL)}$ | \n $=$ | \n$\\dfrac{\\var{gramsb}\\text{ (g)}\\times 100}{\\var{ansb} \\text{ % (w/v)}}$ | \n
\n\n | \n | \n | \n
\n\n| $\\text{volume of solvent (mL)}$ | \n$=$ | \n$\\var{millb} \\text{ (mL)}$ | \n
\n\n
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