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Estimate the electric field strength, $E$, required to make a balloon stick to a ceiling due to electrostatic force. Assume that the balloon has a mass of {massg} g and has an area of contact with the ceiling of {areacm} cm$^2$, and note that the force due to gravity is $mg$ (pointing towards the centre of the Earth).

When providing numerical answers you may express them using scientific notation.  Express values to four significant figures and use the values of physical constants as provided in the course notes.

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The force due to gravity, or weight, at the Earth's surface is written as $mg$, where $m$ is the mass and $g$ is the acceleration due to gravity.  The electric field force can be either written in terms of the force on a charge ($F=qE$), or, as is required in this case, in terms of the energy stored in the field, $F=\\displaystyle{\\varepsilon E^2 A\\over 2}$, where $A$ is the contact area, $\\varepsilon$ is the permittivity of air (a balloon stuck to the ceiling is likely to be in air!) and $E$ is the electric field strength.  For NUMBAS we need to express the electric field as a different symbol as $E$ is reserved as {e}, the base of the natural logarithm.  

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For the electric field to just balance the weight we can equate the two forces and re-arrange for $E$:

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$\\displaystyle{\\varepsilon E^2 A\\over 2}=mg\\Rightarrow E=\\sqrt{\\displaystyle{2mg\\over \\varepsilon A}}$.

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You have to remember that the equations work for SI units, so the mass should be in kg and the area in m$^2$.

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Area in m^2

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Relative permittivity of air.

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Mass of the balloon in g.

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Acceleration due to gravity on Earth, m/s^2

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Computed E-field that JUST balances the weight.  

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Mass in kg.

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Permittivity of free space, F/m.

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Area of contact in cm^2

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The force due to gravity, i.e. the weight of the balloon is given by the expression

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$F_{\\rm gravity}=$ [[0]]

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The force from the elecrtic field opposing the weight of the balloon is given by an expression in terms of the permiitivity, $\\varepsilon$ (epsilon), the contact area, $A$ and the electric field strength, $E_1$ (E_1):

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$F_{\\rm electrostatic}=$ [[0]]

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Calculate the value of $E$ that balances the weight.

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$E=$[[0]] V/m

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