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A new way for solving Quadratic Equation:

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The quadratic equation $ax^2+bx+c=0$ can be solved in a different and easy way as follows:

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Let $\\alpha$ and $\\beta$ be the two roots.  Then we know $\\alpha\\times\\beta=\\dfrac{c}{a}$ and $\\alpha+\\beta=-\\dfrac{b}{a}$

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We shall use the property that the roots are equidistant from their average.

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So we can take them as $\\alpha=\\dfrac{1}{2}\\rm{sum}-u$ and $\\beta=\\dfrac{1}{2}\\rm{sum}+u$ Or $\\boxed{\\alpha=-\\dfrac{1}{2}\\dfrac{b}{a}-u}$ and $\\boxed{\\beta=-\\dfrac{1}{2}\\dfrac{b}{a}+u}$ .

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Consequently we have $\\alpha\\times\\beta=\\left(-\\dfrac{1}{2}\\dfrac{b}{a}-u\\right)\\times\\left(-\\dfrac{1}{2}\\dfrac{b}{a}+u\\right)$

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$\\implies \\dfrac{c}{a}=\\dfrac{1}{4}\\dfrac{b^2}{a^2}-u^2\\implies u^2=\\dfrac{1}{4}\\dfrac{b^2}{a^2}-\\dfrac{c}{a}$.

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Simplifying $u^2=\\dfrac{b^2-4ac}{4a^2}\\implies \\boxed{u=\\dfrac{\\sqrt{b^2-4ac}}{2a}}$ .

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Substituting above we get

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$\\alpha=\\dfrac{-b-\\sqrt{b^2-4ac}}{2a}$ and $\\beta=\\dfrac{-b+\\sqrt{b^2-4ac}}{2a}$.

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Note : $\\boxed{\\alpha=\\rm{average}-u}$ and $\\boxed{\\beta=\\rm{average}+u}$

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______________________________________________________________________________________________________________________________

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Let us consider the following example:

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$x^2-5x+6=0$ .

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We generally start from the product $6$ and find factors by inspection so that the sum will be $5$. In stead, in this method we start from the sum and find $u$.

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Now sum of roots$=5\\implies \\rm{average}=\\dfrac{5}{2}$.

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So roots are $\\dfrac{5}{2}-u$ and $\\dfrac{5}{2}+u$ .

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Therefore product of roots $=\\dfrac{25}{4}-u^2\\implies 6=\\dfrac{25}{4}-u^2\\implies u^2=\\dfrac{25}{4}-6\\implies u^2=\\dfrac{1}{4}\\implies u=\\pm\\dfrac{1}{2}$.

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So roots are $\\dfrac{5}{2}-\\dfrac{1}{2}$ and $\\dfrac{5}{2}+\\dfrac{1}{2}$ . Or roots are $2$ and $3$. 

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______________________________________________________________________________________________________________________________               

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First coefficient

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random

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Sum of the roots

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product of the roots

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Distance of the root from the average

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Average of the roots

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Average-u

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Average+u

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Discriminant of the equation

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Increment on a

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PRACTICE EXERCISE:

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Solve the equation $\\simplify{{a}x^2+{b}x+{c}=0}$

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Fill in the gaps below.

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a=[[0]]

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b=[[1]]

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c=[[2]]

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Sum of roots=[[3]]

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Avg(Average of roots)=[[4]]

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$b^2$=[[5]]

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$4ac$=[[6]]

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Discriminant $(b^2-4ac)$=[[7]]

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$u\\left(=\\dfrac{\\sqrt{b^2-4ac}}{2a}\\right)$=[[8]]

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$\\alpha(=Avg-u)$=[[9]]

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$\\beta(=Avg+u)$=[[10]]

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