Quadratic factorisation that does not rely upon pattern matching.
", "licence": "Creative Commons Attribution-ShareAlike 4.0 International"}, "statement": "Consider the quadratic $ \\simplify[all,expandBrackets]{({a}*x + {b})*(x+{c})}$.
", "advice": "You can use many methods to factorise the qudratic PSF and PSF like crossswords and those metioned below.
\nIf you are having difficulty see your teacher ASAP.
\nYou can use the quadratic formula to deduce that $\\simplify[all,expandBrackets]{({a}*x + {b})*(x+{c})}$ has roots:
\n$ x = \\frac{\\simplify{-({a}*{c}+{b})}\\pm\\sqrt{ (\\var{a*c+b})^2 - 4\\times(\\var{a})\\times(\\var{b*c}) }}{2\\times \\var{a}} = \\var{-1*c} \\text{ or } \\displaystyle \\simplify{-1*{b}/{a}}.$
\nThe roots determine the factors, but only upto a constant. In general, a quadratic with roots $ \\var{-1*c}$ and $\\simplify{-1*{b}/{a}}$ has the form:
\n$C \\times (x + \\simplify{{b}/{a}}) \\times (x - \\var{-1*c})$
\nfor some constant term $C$. The only thing left to do is determine the value of the constant which makes:
\n$C \\times (x + \\simplify{{b}/{a}}) \\times (x - \\var{-1*c}) = \\simplify[all,expandBrackets]{({a}*x + {b})*(x+{c})}$.
\nEquating the coefficients of the $x^2$ terms in the left and right hand sides shows that $C=\\var{a}$. So
\n$ (\\var{a}x + \\var{b}) \\times (x-\\var{-1*c}) = \\simplify[all,expandBrackets]{({a}*x + {b})*(x+{c})}$.
", "rulesets": {}, "extensions": [], "variables": {"c": {"name": "c", "group": "Ungrouped variables", "definition": "random(-5..-1)", "description": "", "templateType": "anything"}, "b": {"name": "b", "group": "Ungrouped variables", "definition": "random(1..5)", "description": "", "templateType": "anything"}, "a": {"name": "a", "group": "Ungrouped variables", "definition": "random(2..3)", "description": "a
", "templateType": "anything"}}, "variablesTest": {"condition": "", "maxRuns": 100}, "ungrouped_variables": ["a", "b", "c"], "variable_groups": [], "functions": {}, "preamble": {"js": "", "css": ""}, "parts": [{"type": "gapfill", "useCustomName": false, "customName": "", "marks": 0, "showCorrectAnswer": true, "showFeedbackIcon": true, "scripts": {}, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "adaptiveMarkingPenalty": 0, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "prompt": "What are the the two factors of this quadratic?
\nEnter your answers below eg x+3 and x-2
\n([[0]]) and ([[1]])
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Make sure there is exactly one root in gap0\n \n var root0 = -1*b/a;\n var root1 = -1*c;\n var correctanswer = a + \"*x*x + (\" +(b+c*a) + \")*x\" + b*c;\n var gap0root0 = (\"0\" == unwrap(this.question.scope.evaluate(gap0,{\"x\": root0})));\n var gap0root1 = (\"0\" == unwrap(this.question.scope.evaluate(gap0,{\"x\": root1})));\n \n // check that gap0 is linear by verifying that it increases by\n // the same constant amount from 10 to 11 and 11 to 12.\n var e10 = unwrap(this.question.scope.evaluate(gap0,{\"x\": 10}));\n var e11 = unwrap(this.question.scope.evaluate(gap0,{\"x\": 11}));\n var e12 = unwrap(this.question.scope.evaluate(gap0,{\"x\": 12}));\n if ((e11 == e12) || (e11 - e10 !== e12 - e11)) {\n this.setCredit(0, \"$\" + gap0 + \"$ is not linear. A linear factor is of the form $Ax + B$ for constants $A \\\\neq 0$ and $B$.\");\n } else if ((gap0root0 && !gap0root1) || (!gap0root0 && gap0root1)) {\n // if root0 xor root1 is a root of gap0\n this.setCredit(1, \"$\" + gap0 + \"$ is a linear factor of $\\\\simplify{\" + correctanswer + \"}$.\");\n } else {\n this.setCredit(0, \"$\" + gap0 + \"$ is not a linear factor of $\\\\simplify{\" + correctanswer + \"}$.\" );\n }\n \n \n} catch(e) {\n this.setCredit(0); // if the student's answer isn't a valid expression, give 0 credit\n this.markingComment(e);\n alert(e);\n}", "order": "instead"}}, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "adaptiveMarkingPenalty": 0, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "answer": "({a}*x + {b})", "showPreview": true, "checkingType": "absdiff", "checkingAccuracy": 0.001, "failureRate": 1, "vsetRangePoints": 5, "vsetRange": [0, 1], "checkVariableNames": false, "notallowed": {"strings": ["/"], "showStrings": true, "partialCredit": 0, "message": ""}, "valuegenerators": [{"name": "x", "value": ""}]}, {"type": "jme", "useCustomName": false, "customName": "", "marks": 1, "showCorrectAnswer": true, "showFeedbackIcon": true, "scripts": {"mark": {"script": "\nvar variables = this.question.scope.variables;\nvar unwrap = Numbas.jme.unwrapValue;\n\nvar a = unwrap(variables.a);\nvar b = unwrap(variables.b);\nvar c = unwrap(variables.c);\n\ntry {\n // get the student's answers to the two gaps\n var gap0 = this.parentPart.gaps[0].studentAnswer;\n var gap1 = this.parentPart.gaps[1].studentAnswer;\n \n if (!gap0 || !gap1) {\n return; \n }\n // check that gap1 is linear\n var e10 = unwrap(this.question.scope.evaluate(gap1,{\"x\": 10}));\n var e11 = unwrap(this.question.scope.evaluate(gap1,{\"x\": 11}));\n var e12 = unwrap(this.question.scope.evaluate(gap1,{\"x\": 12}));\n if ((e11 == e12) || (e11 - e10 !== e12 - e11)) {\n this.setCredit(0, \"$\" + gap1 + \"$ is not linear. A linear factor is of the form $Ax + B$ for constants $A \\\\neq 0$ and $B$.\");\n return;\n } \n \n var compare_settings = {};\n compare_settings.checkingType = \"absdiff\";\n compare_settings.vsetRangeStart = -5; //The lower bound of the range to pick variable values from.\n compare_settings.vsetRangeEnd = 5; //The upper bound of the range to pick variable values from.\n compare_settings.vsetRangePoints = 5; //The number of values to pick for each variable.\n compare_settings.checkingAccuracy = 0.1; // A parameter for the checking function to determine if two results are equal. 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