// Numbas version: finer_feedback_settings {"name": "SG_Elasticiteiten", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "SG_Elasticiteiten", "tags": [], "metadata": {"description": "
Bereken elasticiteiten horend bij een gegeven Stone-Geary nutsfunctie.
", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "Stap 1: Formuleer het maximalisatieprobleem.
Noteer voor de prijs per eenheid van deze producten resp. $p_1 $ en $p_2 $, met als budget $ y $ (dit budget wordt volledig gespendeerd aan deze beide producten).
\\begin{eqnarray}
\\max_{q_1,q_2} U(q_1,q_2) &=& {\\var{c1}} \\cdot (q_1-{\\var{a1}})^{1 / {\\var{n1}}} \\cdot (q_2-{\\var{a2}})^{{\\var{n1min1}} / {\\var{n1}}}
\\mbox{als} && p_1 \\cdot q_1 + p_2 \\cdot q_2 = y
\\end{eqnarray}
wat equivalent is met
\\begin{eqnarray}
\\max_{q_1,q_2} ln U(q_1,q_2) &=& ln({\\var{c1}}) + {\\frac{1}{\\var{n1}}} \\cdot ln(q_1-{\\var{a1}}) + {\\frac{\\var{n1min1}}{\\var{n1}}} \\cdot ln(q_2-{\\var{a2}}) \\\\
\\mbox{als} && p_1 \\cdot q_1 + p_2\\cdot q_2 = y
\\end{eqnarray}
Stap 2: Bepaal de Lagrangefunctie.
\\begin{eqnarray}
L(q_1, q_2, \\lambda) &=& ln U(q_1,q_2) + \\lambda \\cdot (y - p_1 \\cdot q_1 - p_2 \\cdot q_2)
&=& ln({\\var{c1}}) + {\\frac{1}{\\var{n1}}} \\cdot ln(q_1-{\\var{a1}}) + {\\frac{\\var{n1min1}}{\\var{n1}}} \\cdot ln(q_2-{\\var{a2}}) + \\lambda \\cdot ( y - p_1 \\cdot q_1 - p_2\\cdot q_2 )
\\end{eqnarray}
Stap 3: Schrijf de eerste orde voorwaarden neer om de kritische punten van deze Lagrangefunctie te berekenen.
\\begin{eqnarray}
\\mbox{(1) } \\quad \\frac{\\partial {L}}{\\partial q_1} & = & {\\frac{1}{\\var{n1}}} \\cdot {\\frac {1} {q_1-{\\var{a1}}} } - \\lambda \\cdot p_1 = 0 \\\\
\\mbox{(2) } \\quad \\frac{\\partial {L}}{\\partial q_2} & = & {\\frac{\\var{n1min1}}{\\var{n1}}} \\cdot {\\frac {1} {q_2-{\\var{a2}}}} - \\lambda \\cdot p_2 = 0 \\\\
\\mbox{(3) } \\quad \\frac{\\partial {L}}{\\partial \\lambda} & = & y - p_1 \\cdot q_1 - p_2 \\cdot q_2 = 0
\\end{eqnarray}
Stap 4: Los dit stelsel vergelijkingen op naar $q_1$, $q_2$ en $\\lambda$.
Het oplossen van $\\lambda$ uit de vergelijkingen (1) en (2) levert na gelijkstelling:
\\begin{eqnarray}
{\\frac{1}{\\var{n1}}}\\cdot{\\frac {1} {p_1 \\cdot(q_1-{\\var{a1}})} }& = & {\\frac{\\var{n1min1}}{\\var{n1}}}\\cdot{\\frac {1} {p_2 \\cdot(q_2-{\\var{a2}})}}\\\\ \\\\
{p_2} \\cdot {(q_2-{\\var{a2}})} & = & {\\var{n1min1}} \\cdot {p_1} \\cdot {(q_1-{\\var{a1}})} \\\\ \\\\
\\mbox{(4)} \\quad \\quad \\quad {p_2} \\cdot {q_2} & = & {\\var{a2}} \\cdot {p_2} + {\\var{n1min1}} \\cdot {p_1} \\cdot {(q_1-{\\var{a1}})}
\\end{eqnarray}
d.w.z.
\\begin{eqnarray}
{q_2} & = & {\\var{a2}} + {\\frac {1} {p_2}} \\cdot {\\var{n1min1}} \\cdot {p_1} \\cdot {(q_1-{\\var{a1}})}
\\end{eqnarray}
Substitueer (4) in de budgetrestrictie:
\\begin{eqnarray}
{p_1} \\cdot {q_1} + {\\var{a2}} \\cdot {p_2} + {\\var{n1min1}} \\cdot {p_1}\\cdot {(q_1-{\\var{a1}})} & = & y\\\\
{p_1} \\cdot {q_1} + {\\var{a2}} \\cdot {p_2} + {\\var{n1min1}} \\cdot {p_1} \\cdot{q_1} - {\\var{n1min1}} \\cdot {\\var{a1}} \\cdot {p_1} & = & y\\\\
{\\var{n1}} \\cdot {p_1}\\cdot {q_1} & = & y + {\\var{n1min1maala1}} \\cdot {p_1} - {\\var{a2}} \\cdot {p_2} \\\\
{q_1} & = & {\\frac {1}{\\var{n1} \\cdot {p_1}}} \\cdot { ( y + {\\var{n1min1maala1}} \\cdot {p_1} - {\\var{a2}} \\cdot {p_2} ) } \\\\
{q_1} & = & {\\frac {y + {\\var{n1min1maala1}} \\cdot {p_1} - {\\var{a2}} \\cdot {p_2}}{\\var{n1} \\cdot {p_1}}}
\\end{eqnarray}
Substitutie hiervan in bovenstaande uitdrukking voor $q_2$ laat toe om deze $q_2$ te bepalen:
\\begin{eqnarray}
{q_2} & = & \\frac{\\var{t2}\\cdot y-\\var{a1maalt2} \\cdot {p_1} + \\var{a2}\\cdot{p_2}}{\\var{n1} \\cdot {p_2}}
\\end{eqnarray}
De vraagfuncties zijn dus
\\begin{eqnarray}
{q_1} & = & {\\frac {y + {\\var{n1min1maala1}} \\cdot {p_1} - {\\var{a2}} \\cdot {p_2}}{\\var{n1} \\cdot {p_1}}}\\\\
{q_2} & = & \\frac{\\var{t2}\\, y-\\var{a1maalt2}\\cdot{p_1} + \\var{a2}\\cdot {p_2}}{\\var{n1} \\cdot {p_2}}
\\end{eqnarray}
Stap 5: Bereken de elasticiteiten.
\\begin{eqnarray}
{\\varepsilon}^{q_1}_{p_1} & = & {\\frac {{\\partial}{q_1}} {{\\partial} {p_1}}} \\cdot {\\frac {p_1} {q_1}} = {\\frac {1} {{\\var{n1}} }} \\cdot {\\frac {{\\partial}} {{\\partial} {p_1}}} { ( {\\var{n1min1maala1}} + {\\frac {y - {\\var{a2}}\\cdot {p_2}} {p_1}} ) } \\cdot {\\frac {p_1} {q_1}} = - {\\frac {y - {\\var{a2}} \\cdot {p_2}} {{\\var{n1}} \\cdot {p_1} \\cdot {q_1} } } \\quad, {\\mbox{na evaluatie in }}P^*: \\var{epsq1p1} \\\\
{\\varepsilon}^{q_1}_{p_2} & = & {\\frac {{\\partial}{q_1}} {{\\partial} {p_2}}} \\cdot {\\frac {p_2} {q_1}} = - {\\frac {\\var{a2}} {{\\var{n1}} \\cdot {p_1}} } \\cdot {\\frac {p_2} {q_1}} \\quad, {\\ } \\mbox{na evaluatie in } P^*: \\var{epsq1p2} \\\\
{\\varepsilon}^{q_2}_{p_1} & = & {\\frac {{\\partial}{q_2}} {{\\partial} {p_1}}} \\cdot {\\frac {p_1} {q_2}} = - {\\frac {\\var{n1min1maala1}} {{\\var{n1}} \\cdot {p_2}} } \\cdot {\\frac {p_1} {q_2}} \\quad , \\mbox{na evaluatie in }P^*: \\var{epsq2p1} \\\\
{\\varepsilon}^{q_2}_{p_2} & = & {\\frac {{\\partial}{q_2}} {{\\partial} {p_2}}} \\cdot {\\frac {p_2} {q_2}} = {\\frac {1} {{\\var{n1}} }} \\cdot {\\frac {{\\partial}} {{\\partial} {p_2}}} { ( {\\var{a2}} + {\\frac {{\\var{n1min1}} \\cdot y - {\\var{n1min1maala1}} \\cdot {p_1}} {p_2}} ) } \\cdot {\\frac {p_2} {q_2}} = - {\\frac {{\\var{n1min1}} \\cdot y - {\\var{n1min1maala1}} \\cdot {p_1}} {{\\var{n1}} \\cdot {p_2} \\cdot {q_2} } } \\quad , \\mbox{na evaluatie in } P^*: \\var{epsq2p2} \\\\
{\\varepsilon}^{q_1}_{y} & = & {\\frac {{\\partial}{q_1}} {{\\partial} {y}}} \\cdot {\\frac {y} {q_1}} = {\\frac {1} {{\\var{n1}} \\cdot {p_1}} } \\cdot {\\frac {y} {q_1}} , \\mbox{na evaluatie in }P^*: \\var{epsq1y}\\\\
{\\varepsilon}^{q_2}_{y} & = & {\\frac {{\\partial}{q_2}} {{\\partial} {y}}} \\cdot {\\frac {y} {q_2}} = {\\frac {1} {{\\var{n1}}}} \\cdot {\\frac {1} {{\\var{n1min1}} \\cdot {p_2}} } \\cdot {\\frac {y} {q_2}} \\quad , \\mbox{na evaluatie in } P^*: \\var{epsq2y}\\\\
\\end{eqnarray}
Antwoorden:
\n\\[ {\\varepsilon}^{q_1}_{p_1} {( \\var{gegp1} , \\var{gegp2} , \\var{gegy} )} \\approx \\var{benepsq1p1} \\]
\\[ {\\varepsilon}^{q_2}_{p_2} {( \\var{gegp1} , \\var{gegp2} , \\var{gegy} )} \\approx \\var{benepsq2p2} \\]
\\[ {\\varepsilon}^{q_1}_{y} {( \\var{gegp1} , \\var{gegp2} , \\var{gegy} )} \\approx \\var{benepsq1y} \\]
\\[ {\\varepsilon}^{q_2}_{y} {( \\var{gegp1} , \\var{gegp2} , \\var{gegy} )} \\approx \\var{benepsq2y} \\]
\\[ {\\varepsilon}^{q_1}_{p_2} {( \\var{gegp1} , \\var{gegp2} , \\var{gegy} )} \\approx \\var{benepsq1p2} \\]
\\[ {\\varepsilon}^{q_2}_{p_1} {( \\var{gegp1} , \\var{gegp2} , \\var{gegy} )} \\approx \\var{benepsq2p1} \\]
c1
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