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According to the Arrhenius equation

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$lnk=lnA-\\frac{E_a}{RT}$

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where $R$ is the gas constant ($8.314$ $JK^{-1}mol^{-1})$, $T$ is the temperature in Kelvin, $k$ is the rate constant and $A$ is the frequency factor.

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Calculate the activation energy $E_a$ if a plot of $lnk$ against $\\frac{1}{T}$ gives a straight line with a gradient of $-22.7\\times10^3$.

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