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A question testing the application of the Area of a Triangle formula when given two sides and an angle. In these questions, the triangle is always acute and both of the given side lengths are adjacent to the given angle.

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Suppose that $\\Delta ABC$ is a triangle with all interior angles less than $90^\\circ $. Sides and angles are labelled as shown in the diagram below (not to scale).

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Given the following two sides and an angle, find the area of the triangle.

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Use the formula $Area=\\frac{1}{2} bc \\sin A$.

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Hence $Area =\\frac{1}{2}* \\var{b0}*\\var{c0}* \\sin \\var{aa0}=\\var{area}$.

\n

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$A=\\var{AA0}^\\circ$, $b=\\var{b0}$, $c=\\var{c0}$

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Area $=$ [[0]]

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The formula is $Area=\\frac{1}{2} ab\\sin C$, or in this example, $Area= \\frac{1}{2} bc\\sin A$.

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