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Solusi dari persamaan diferensial

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$y^{\"}+4y=8sec^{3}(2x)$

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dengan $y(0)=2$ dan $y'(0)=4$

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adalah

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Ket:

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tulis ekspresi fungsinya saja (dalam x)

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perkalian gunakan * (contoh x*sin(x))

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pangkat dan sinus gunakan tanda kurung (contoh e^(-x), sin(x))

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invers trigonometri gunakan arcsin(x), arccos(x), arctan(x)

", "advice": "

$y=cos(2x)+2sin(2x)+\\frac{1}{cos(2x)}

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