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Based on your lab measurements, calculate the theoretical balancing mass corresponding to each of the five depths registered in the lab. You will need to calculate multiple intermediate variables at each depth, these are the hydrostatic thrust, F [N]; the depth of the centre of pressure, h0 [m]; and the turning moment at the pivot, M [Nm]. The details on how to calculate these variables is present in the lab handouts available [HERE]. 

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For a partially submerged plane, e.g. when using the 0.15 kg mass, we have:

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Using an example result for submerged depth, d = {d3} [m]      

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The hydrostatic thrust, F = g*rho*A*h_bar = 9.81*1000*(0.075*{d3})*({d3}/2) = {F3} [N]

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The depth of the centre of pressure, h0 = 2/3*d = 2*{d3}/3 = {h_03} [m]

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The moment at the pivot, M = F*h\" = F*(h0+(H-d)) = {F3}*({h_03}+0.2-{d3}) = {M3} [Nm]

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Finally, the theoretical balancing mass, mth = M/(L*g) = {M3}/(0.275*9.81) = {tM3} [kg]

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For a completely submerged plane, e.g. when using the 0.33 kg mass, we have:

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Example d = {d5} [m]

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The hydrostatic thrust F = g*rho*A*h_bar, where A = BD and h_bar = d - D/2, therefore: F = 9.81*1000*(0.075*0.1)*({d5}-0.1/2) = {F5s} [N]

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The depth of the centre of pressure, h0 = h_bar + Ig/(A*h_bar), where Ig = BD3/12, therefore h0 = ({d5}-0.1/2)+((0.075*0.1^3)/12)/((0.075*0.1)*({d5}-0.1/2)) =  {h_05s} [m]

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The moment at the pivot, M = F*h\" = F*(h0+(H-d)) = {F5s}*({h_05s}+0.2-{d5}) = {M5s} [Nm]

\n

Finally, the theoretical balancing mass, mth = M/(L*g) = {M5s}/(0.275*9.81) = {tM5s} [kg]

\n

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Hydrostatic thrust at the first mass' depth. 

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Depth of centre of pressure 1 [m]

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Turning moment at pivot [Nm]

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Theoretical Balancing Mass [kg]

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Centre of pressure (measured from water surface) (m)

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Moment at pivot (Nm)

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Centre of pressure (measured from water surface) (m)

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Moment at pivot (Nm)

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Centre of pressure (measured from water surface) (m)

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Moment at pivot (Nm)

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Submerged case

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Moment at pivot (Nm)

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Centre of pressure (measured from water surface) (m)

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Distance from weight hanger to pivot (m)

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Distance from base of quadrant face to pivot (m)

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Height of vertical quadrant face (m)

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Width of vertical quadrant face (m)

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Experimental balancing mass 1 (kg)

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Experimental balancing mass 2 (kg)

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Experimental balancing mass 3 (kg)

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Experimental balancing mass 4 (kg)

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Experimental balancing mass 5 (kg)

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Write the depth of immersion when using the 0.05 kg mass: [[0]]

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Write the corresponding theoretical balancing mass: [[1]]

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Write the depth of immersion when using the 0.10 kg mass: [[0]]

\n

Write the corresponding theoretical balancing mass: [[1]]

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Write the depth of immersion when using the 0.15 kg mass: [[0]]

\n

Write the corresponding theoretical balancing mass: [[1]]

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If the plane was partially submerged answer this part, otherwise answer part e). 

\n

Write the depth of immersion when using the 0.23 kg mass: [[0]]

\n

Write the corresponding theoretical balancing mass: [[1]]

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Answer this part if the plane was completely submerged when using the 0.23 kg mass. 

\n

Write the depth of immersion when using the 0.23 kg mass: [[0]]

\n

Write the corresponding theoretical balancing mass: [[1]]

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Write the depth of immersion when using the 0.33 kg mass: [[0]]

\n

Write the corresponding theoretical balancing mass: [[1]]

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