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The symbol $i$ is such that:

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\\[   i^2=-1  \\]

", "advice": "

We are asked to evaluate the following, applying the definition that 

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\\[   i^2=-1  \\]

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$\\large i^2$          That is:  $ \\sqrt{-1} \\times   \\sqrt{-1}  $  or  $i \\times i$. This one is straightforward from the definition of $i$;

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$\\large i^2=-1$ 

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$\\large i^3$          That is:  $ \\sqrt{-1} \\times   \\sqrt{-1} \\times   \\sqrt{-1} $ 

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Notice that the first two could be written as  $-1$ so this becomes  $-1 \\times i$

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$\\large i^3=-i$ 

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$\\large i^4$          That is:  $ \\sqrt{-1} \\times   \\sqrt{-1} \\times   \\sqrt{-1}  \\times   \\sqrt{-1} $  

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Remember that \"pairs\" become $-1$ and this becomes $-1 \\times -1$

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$\\large i^4=1$ 

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$\\large i^5$          That is:  $ \\sqrt{-1} \\times   \\sqrt{-1} \\times   \\sqrt{-1}  \\times   \\sqrt{-1}  \\times   \\sqrt{-1} $  

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From the previous example, this becomes  $1 \\times i$

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$\\large i^5=i$ 

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$\\large i^6$          That is:  $ \\sqrt{-1} \\times   \\sqrt{-1} \\times   \\sqrt{-1}  \\times   \\sqrt{-1}  \\times   \\sqrt{-1}   \\times   \\sqrt{-1}$  

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Again, thinking in \"pairs\" we have  $-1 \\times -1 \\times -1$

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$\\large i^6=-1$ 

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Evaluate the following:

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(Hint: use previous answers to inform later ones)

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$\\large i^2$          That is:  $ \\sqrt{-1} \\times   \\sqrt{-1}  $

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$\\large i^2=$ [[0]]

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$\\large i^3$          That is:  $ \\sqrt{-1} \\times   \\sqrt{-1} \\times   \\sqrt{-1} $ 

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$\\large i^3=$ [[1]]

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$\\large i^4$          That is:  $ \\sqrt{-1} \\times   \\sqrt{-1} \\times   \\sqrt{-1}  \\times   \\sqrt{-1} $  

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$\\large i^4=$ [[2]]

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$\\large i^5$          That is:  $ \\sqrt{-1} \\times   \\sqrt{-1} \\times   \\sqrt{-1}  \\times   \\sqrt{-1}  \\times   \\sqrt{-1} $  

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$\\large i^5=$ [[3]]

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$\\large i^6$          That is:  $ \\sqrt{-1} \\times   \\sqrt{-1} \\times   \\sqrt{-1}  \\times   \\sqrt{-1}  \\times   \\sqrt{-1}   \\times   \\sqrt{-1}$  

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$\\large i^6=$ [[4]]

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Apply this to the following, randomly generated examples, without hints.

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Evaluate:

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$ \\large i^{\\var{P1}}=$ [[0]]

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Evaluate:

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$ \\large i^{\\var{P2}}=$ [[1]]

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Evaluate:

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$ \\large i^{\\var{P3}}=$ [[2]]

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