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Let $f(x) = 2 \\ln(x-3)$. The following diagram shows part of the graph of $f$.

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This is a log graph which has been shifted and stretched. The shift is three units to the right and so the vertical asymptote has equation $x = 3$ the x-intercept is when the function evaluates to zero. This is when $\\ln(x-3) = 0$ and so when $x-3=1$. Therefore the x-intercept is at $(4,0)$.

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Write down the equation of the vertical asymptote.

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Write down the coordinate of the x-intercept.

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([[0]],[[1]])

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