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This question is about the electric field a distance from a point charge in vacuum.  Coulomb's law states that the electric field from a point charge in vacuum is
$\\displaystyle{q\\over4\\pi\\varepsilon_0r^2}$.
When providing numerical answers you may express them using scientific notation.  Express values to four significant figures and use the values of physical constants as provided in the course notes.

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You might have calculated the force on the second point charge using the full Coulomb force formula,

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$\\displaystyle F={q_1q_2\\over4\\pi\\varepsilon r^2}$ 

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If you approached the question this way you have missed a functional use of the electric field as it provides directly the potential for a force to exist, so that $\\vec{F}=q\\vec{E}$.

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Common errors include unit slips and forgetting to square the distance.

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The force due to q1 experienced by q2 (N).

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r1 in m

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The second point charge (nC).

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Electric field strength in SI units for a point charge.

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Random distance between 1 and 10 mm in steps of 1 mm (unit are mm)

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Random (point) charge between -10 and +10 nC.

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Permitivitty of free space in F/m.

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q2 in C.

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q1 in C

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Calculate the magnitude of $E$ at a distance {r1} mm from a {q1} nC point-charge.

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$|\\vec{E}|=$ [[0]] V/m.

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A second point charge of magnitude {q2} nC is placed at the distance of {r1} mm from the original {q1} nC point charge.  What is the magnitude of the force it will experience?

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$|\\vec{F}|=$ [[0]] Newtons.

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