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Determinant of 2x2 and notation

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Input answer only.

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The determinant of the matrix:

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$\\large A= \\left( \\begin{array}{ccc} a & b  \\\\ c & d  \\end{array} \\right) $  is denoted by   $\\large \\left| \\begin{array}{ccc} a & b  \\\\ c & d  \\end{array} \\right| $

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and is defined to be the number  $ad-bc$. That is:

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$\\large \\left| \\begin{array}{ccc} a & b  \\\\ c & d  \\end{array} \\right| =ad-bc$

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We can use the notation  $det(A)$  or  $|A|$  or  $\\Delta$  to denote the determinant of $A$.

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We are asked to calculate the determinants of some  $2 \\times 2$  matrices:

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 We simply have to carry out this calculation for each one,

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$\\large \\left| \\begin{array}{ccc} a & b  \\\\ c & d  \\end{array} \\right| =ad-bc$

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 $A=\\var{A}$

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$|A|=\\left|\\begin{array}{ccc}\\var{A[0][0]} & \\var{A[0][1]} \\\\\\var{A[1][0]} & \\var{A[1][1]} \\end{array}\\right| =\\var{Apart1}\\large -\\var{Apart2}=\\var{detA}$

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 $B=\\var{B}$

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$|B|=\\left|\\begin{array}{ccc}\\var{B[0][0]} & \\var{B[0][1]} \\\\\\var{B[1][0]} & \\var{B[1][1]} \\end{array}\\right| =\\var{Bpart1}\\large -\\var{Bpart2}=\\var{detB}$

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 $C=\\var{C}$

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$|C|= \\left|\\begin{array}{ccc}\\var{C[0][0]} & \\var{C[0][1]} \\\\\\var{C[1][0]} & \\var{C[1][1]} \\end{array}\\right| =\\var{Cpart1}\\large -\\var{Cpart2}=\\var{detC}$

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$D=\\var{D}$

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$|D|= \\left|\\begin{array}{ccc}\\var{D[0][0]} & \\var{D[0][1]} \\\\\\var{D[1][0]} & \\var{D[1][1]} \\end{array}\\right| =\\var{Dpart1}\\large -\\var{Dpart2}=\\var{detD}$

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Calculate the determinants of the following matrices:

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 $A=\\var{A}$

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$|A|=\\left|\\begin{array}{ccc}\\var{A[0][0]} & \\var{A[0][1]} \\\\\\var{A[1][0]} & \\var{A[1][1]} \\end{array}\\right| =$ [[0]]

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 $B=\\var{B}$

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$|B|=\\left|\\begin{array}{ccc}\\var{B[0][0]} & \\var{B[0][1]} \\\\\\var{B[1][0]} & \\var{B[1][1]} \\end{array}\\right| =$ [[1]]

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$C=\\var{C}$

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$|C|=\\left|\\begin{array}{ccc}\\var{C[0][0]} & \\var{C[0][1]} \\\\\\var{C[1][0]} & \\var{C[1][1]} \\end{array}\\right|=$ [[2]]

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$D=\\var{D}$

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$|D|= \\left|\\begin{array}{ccc}\\var{D[0][0]} & \\var{D[0][1]} \\\\\\var{D[1][0]} & \\var{D[1][1]} \\end{array}\\right| =$ [[3]]

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