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Simplifying an expression of the form $\\frac{a^4b^3}{\\sqrt{a^4b^2}}$ to $a^2b^2$, for integers $a$ and $b$.

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Calculate the following expression without a calculator:

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\\[ \\frac{\\var{a}^\\var{n} \\times \\var{b}^\\var{m}}{\\sqrt{\\var{a^4} \\times \\var{b^2}}} \\]

", "advice": "

To simplify $\\frac{\\var{a}^\\var{n} \\times \\var{b}^\\var{m}}{\\sqrt{\\var{a^4} \\times \\var{b^2}}}$, we want to make use of the following 2 rules:

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    \n
  1. $\\sqrt{a \\times b} = \\sqrt{a} \\times \\sqrt{b}$;
  2. \n
  3. $\\frac{a^n}{a^m} = a^{n-m}$.
  4. \n
\n

Applying rule 1 to the denominator:

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\\[ \\begin{split}\\frac{\\var{a}^\\var{n} \\times \\var{b}^\\var{m}}{\\sqrt{\\var{a^4} \\times \\var{b^2}}} &\\,= \\frac{\\var{a}^\\var{n} \\times \\var{b}^\\var{m}}{\\sqrt{\\var{a^4}} \\times \\sqrt{\\var{b^2}}} \\\\\\\\ &\\,= \\frac{\\var{a}^\\var{n} \\times \\var{b}^\\var{m}}{\\var{a^2} \\times \\var{b}}. \\end{split}\\]

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Since $\\var{a^2} = \\var{a}^2$, we can rewrite the denominator so that the numerator and denominator are both in terms of $\\var{a}$ and $\\var{b}$, allowing us to apply rule 2:

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\\[ \\begin{split} \\frac{\\var{a}^\\var{n} \\times \\var{b}^\\var{m}}{\\var{a^2} \\times \\var{b}} &\\,= \\frac{\\var{a}^\\var{n} \\times \\var{b}^\\var{m}}{\\var{a}^2 \\times \\var{b}} \\\\\\\\ &\\,= \\var{a}^{\\var{n}-2} \\times \\var{b}^{\\var{m}-1} \\\\ &\\,= \\var{a}^\\var{n-2} \\times \\var{b}^\\var{m-1} . \\end{split} \\]

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Therefore,

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\\[ \\begin{split} \\frac{\\var{a}^\\var{n} \\times \\var{b}^\\var{m}}{\\sqrt{\\var{a^4} \\times \\var{b^2}}} &\\,= \\var{a}^\\var{n-2} \\times \\var{b}^\\var{m-1} \\\\ &\\,= \\var{a^(n-2)*b^(m-1)}. \\end{split} \\]

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