// Numbas version: exam_results_page_options {"name": "Use formulae for the area and volume of geometric shape", "extensions": ["geogebra"], "custom_part_types": [], "resources": [["question-resources/icecrea_QqVaCIf.svg", "/srv/numbas/media/question-resources/icecrea_QqVaCIf.svg"], ["question-resources/frisbee_variable_TESZa4J.svg", "/srv/numbas/media/question-resources/frisbee_variable_TESZa4J.svg"], ["question-resources/tennis-ball_with_variable_MBOLQeM.svg", "/srv/numbas/media/question-resources/tennis-ball_with_variable_MBOLQeM.svg"]], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "Use formulae for the area and volume of geometric shape", "tags": [], "metadata": {"description": "

Substitute values into formulae for the area or volume of various geometric objects.

", "licence": "Creative Commons Attribution 4.0 International"}, "statement": "

Answer the following questions by substituting the correct values into the given equations.

", "advice": "

When inserting numbers into your calculator, make sure that you place brackets correctly.

\n

a) 

\n

We can see from the diagram that the radius of the frisbee is $\\var{mccall[2]}$ $\\mathrm{cm}$.
Replacing the letter $r$ in the formula for the area of a circle with $\\var{mccall[2]}$ gives,

\n

\\begin{align}
\\mathrm{Area} &= \\pi r^2 \\\\
&= \\pi\\times(\\var{mccall[2]})^2 \\\\
&= \\var{dpformat((mccall[2])^2, 2)}\\pi\\, \\mathrm{cm}^2 \\\\
&= \\var{dpformat(pi (mccall[2])^2, 2)}\\, \\mathrm{cm}^2 \\quad \\text{to 2 d.p.}  
\\end{align}

\n

\n

b) 

\n

We can see from the diagram that the radius of the cone is $\\var{r}$ $\\mathrm{cm}$ and the height is $\\var{h}$ $\\mathrm{cm}$.
Replacing the letters $r$ and $h$ in the formula for the volume of a cone with $\\var{r}$ $\\mathrm{cm}$ and $\\var{h}$ $\\mathrm{cm}$ respectively gives,

\n

\\begin{align}
\\mathrm{Volume} &= \\frac{h}{3} \\pi r^2 \\\\
&= \\frac{(\\var{h})}{3} \\times \\pi \\times (\\var{r})^2 \\\\
&= \\var{dpformat((pi)*(h/3)*(r)^2 , 5)}\\, \\mathrm{cm}^3 \\\\
&=\\var{dpformat(h/3 * pi * (r)^2, 1)}\\, \\mathrm{cm}^3 \\quad \\text{to 1 d.p.} \\\\
\\end{align}

\n

\n

c)

\n

We can see from the diagram that the radius of the tennis ball is $\\var{mccall[1]}$ $\\mathrm{cm}$.
Replacing the letter $r$ in the formula for the volume of a sphere with $\\var{mccall[1]}$ gives,

\n

\\begin{align}
\\mathrm{Volume} &= \\frac{4}{3} \\pi r^3 \\\\
&= \\frac{(4)}{(3)} \\times \\pi \\times (\\var{mccall[1]})^3 \\\\
&= \\var{dpformat((4/3)*pi*mccall[1]^3, 5)}\\,  \\mathrm{cm}^3 \\\\
&= \\var{precround(((4/3)* pi) *(mccall[1])^3, 1)}\\, \\mathrm{cm}^3 \\quad \\text{to 1 d.p.} \\\\
\\end{align}

\n

\n

d)

\n

We can see from the diagram that the trapezium has two parallel sides with length $\\var{trap_length_a}$ $\\mathrm{cm}$, $\\var{trap_length_b}$ $\\mathrm{cm}$ and height $\\var{trap_h}$ $\\mathrm{cm}$.
Replacing the letters $a$, $b$ and $h$ in the formula for the area of a trapezium with $\\var{trap_length_a}$, $\\var{trap_length_b}$ and $\\var{trap_h}$ respectively gives, 

\n

\n

\\begin{align}
\\mathrm{Area} &= \\frac{1}{2} (a + b) h \\\\
&= \\frac{1}{2} \\times (\\var{trap_length_a} + \\var{trap_length_b}) \\times \\var{trap_h} \\\\
&= \\var{precround((0.5) (trap_length_a + trap_length_b) trap_h, 1)}\\, \\mathrm{cm}^2 \\quad \\text{to 1 d.p.} \\\\
\\end{align}

\n

\\begin{align}
\\mathrm{Area} &= \\frac{1}{2} (a + b) h \\\\
&= \\frac{1}{2} \\times (\\var{trap_length_a} + \\var{trap_length_b}) \\times \\var{trap_h} \\\\
&= \\var{precround((0.5)(trap_length_a +trap_length_b) trap_h, 2)}\\, \\mathrm{cm}^2 \\\\
&= \\var{precround((0.5) (trap_length_a + trap_length_b) trap_h, 1)}\\, \\mathrm{cm}^2 \\quad \\text{to 1 d.p.} \\\\
\\end{align}

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Rounded value for the length of c.

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Defines the point for the height of the trapezium.

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A random variable which will be inputted by the student.

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The constant coefficient

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List of names to randomise. Can change to any name inserted

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Rounded value for the length of b.

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For triangle - The length of the vector BC

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Rounded theta value. 

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For triangle - The length of the vector AC 

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Position of point B in Geogebra. This point is randomised to make the triangles different.

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Defines the pronoun in the question.

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Definition of the points to put into Geogebra

", "templateType": "anything"}, "h": {"name": "h", "group": "Cone variables", "definition": "random(11..17#0.1)", "description": "

The height for volume of a cone.

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Height of the trapezium

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This calculates the area of the triangle for part b)

", "templateType": "anything"}, "b": {"name": "b", "group": "Triangle variables", "definition": "vector(-3,0)", "description": "

Position of the point A in Geogebra. This point is fixed so the triangle doesn't hang in one corner or the whole page.

", "templateType": "anything"}, "n": {"name": "n", "group": "Name variables", "definition": "random(0..4#1)", "description": "

n is a random number between 0 and 4 that picks a name from {name} and then picks the next in the list for the other name such that there is always a male and a female in the question. 

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List of names to randomise. Can change to any name inserted

", "templateType": "anything"}, "trap_rand": {"name": "trap_rand", "group": "Trapezium variables", "definition": "random(1..3#1)", "description": "

A random number to define the height of the trapezium.

", "templateType": "anything"}, "c_theta": {"name": "c_theta", "group": "Triangle variables", "definition": "(180/pi)*arccos(((length_b)^2+(length_c)^2-(length_a)^2)/(2(length_b)(length_c))) ", "description": "

Theta is randomised by the lengths 

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Calculates the area of the trapezium

", "templateType": "anything"}, "defs": {"name": "defs", "group": "Triangle variables", "definition": "[\n ['A',a],\n ['B',b],\n ['C',c]\n ]", "description": "

Creates the points in Geogebra is not used directly in the question but to create the image in Geogebra.

", "templateType": "anything"}, "length_a": {"name": "length_a", "group": "Triangle variables", "definition": "sqrt((a[0]-b[0])^2+(a[1]-b[1])^2)", "description": "

For triangle - The length of the vector AB

", "templateType": "anything"}, "trap_d": {"name": "trap_d", "group": "Trapezium variables", "definition": "vector(random(5..7#0.1), -4)", "description": "

Creates the point D on the trapezium

", "templateType": "anything"}, "c": {"name": "c", "group": "Triangle variables", "definition": "vector(\n random(2..5#0.1),\n random(2..5#0.1)\n )", "description": "

Triangle - A variable point which ultimately decides how the triangle looks.

", "templateType": "anything"}, "trap_a": {"name": "trap_a", "group": "Trapezium variables", "definition": "vector(1,-4)", "description": "

Creates the point A on the trapezium

", "templateType": "anything"}, "trap_c": {"name": "trap_c", "group": "Trapezium variables", "definition": "vector(random(4..5.5#0.1), trap_rand)", "description": "

Creates the point C on the trapezium

", "templateType": "anything"}, "mccall": {"name": "mccall", "group": "RNG", "definition": "[0,random(3.1..3.7#0.1),random(5..20#0.1)]\n", "description": "

Matrix of random variables used to create length in the questions.

", "templateType": "anything"}, "x2": {"name": "x2", "group": "Quadratic variables", "definition": "random(1..10#1)", "description": "

The x^2 coefficient

", "templateType": "anything"}, "trap_areadp2": {"name": "trap_areadp2", "group": "Trapezium variables", "definition": "precround(0.5*(trap_length_a + trap_length_b)*trap_h, 2)", "description": "", "templateType": "anything"}, "trap_b": {"name": "trap_b", "group": "Trapezium variables", "definition": "vector(random(1.5..2.5#0.1), trap_rand)", "description": "

Creates the point B on the trapezium

", "templateType": "anything"}, "x1": {"name": "x1", "group": "Quadratic variables", "definition": "random(1..50)", "description": "

The x coefficient

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Calculate the area of a frisbee, assuming that the frisbee can be modelled as a circle, given the formula for the area of a circle is

\n

\\[\\mathrm{Area} = \\pi r^2.\\]

\n

\n

$\\mathrm{Area}$ = [[0]] $\\mathrm{cm}^2$    Round your answer to 2 decimal places.

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Calculate the volume of a cone given the formula for the volume of a cone is

\n

\\[\\mathrm{Volume} = \\frac{h}{3} \\pi r^2.\\]

\n

\n

$\\mathrm{Volume}$ = [[0]] $\\mathrm{cm}^3$   Round your answer to 1 decimal place.

\n

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{name[n]} has a tennis ball and {pronoun} wants to find the volume of the ball. Using the diagram and the formula for the volume of a sphere, calculate the volume of the ball. 

\n

\\[\\mathrm{Volume}= \\frac{4}{3} \\pi r^3.\\]

\n

\n

$\\mathrm{Volume}$ = [[0]] $\\mathrm{cm}^3$   Round your answer to 1 decimal place.

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Find the area of the trapezium given the formula for the area of a trapezium is

\n

\\[\\mathrm{Area} = \\frac{1}{2}(a+b) h .\\]

\n

{geogebra_applet('https://www.geogebra.org/m/Gtjzajb6',trap_defs)}

\n

\n

All lengths are given in metres.

\n

$\\mathrm{Area}$ = [[0]] $\\mathrm{m}^2$   Round your answer to 1 decimal place.

\n

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