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Rewriting fractional expressions involving $\\sqrt[n]{x^m}$ using rules to combine and simplify indices. 

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Rewrite the following expression as a single term, in the form $x^n$, where $n$ is a fraction.

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\\[ \\simplify[!collectNumbers]{root(x^{n}x^{m},{p})/(root(x,{q})root(x^{q},{2q}))} \\]

", "advice": "

To rewrite $\\dfrac{\\sqrt[\\var{p}]{x^\\var{n}x^\\var{m}}}{\\sqrt[\\var{q}]{x}\\sqrt[\\var{2q}]{x^\\var{q}}}$ in the form $x^n$, we need to use the following rules:

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    \n
  1. $a^n a^m = a^{n+m}$;
  2. \n
  3. $\\sqrt[n]{a} = a^{1/n}$;
  4. \n
  5. $\\left(a^n\\right)^m = a^{n \\times m}$;
  6. \n
  7. $\\frac{a^n}{a^m} = a^{n-m}$.
  8. \n
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We will simplify the numerator and denominator sepearately to make the steps clearer. Firstly, applying rule 1, then rule 2, and then rule 3 to the numerator:

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\\[ \\begin{split}\\dfrac{\\sqrt[\\var{p}]{x^\\var{n}x^\\var{m}}}{\\sqrt[\\var{q}]{x}\\sqrt[\\var{2q}]{x^\\var{q}}} &\\,=\\dfrac{\\sqrt[\\var{p}]{x^{\\var{n+m}}}}{\\sqrt[\\var{q}]{x}\\sqrt[\\var{2q}]{x^\\var{q}}} \\\\\\\\&\\,=\\dfrac{\\left(x^\\var{n+m}\\right)^\\simplify[fractionNumbers]{{1/p}}}{\\sqrt[\\var{q}]{x}\\sqrt[\\var{2q}]{x^\\var{q}}} \\\\\\\\ &\\,= \\dfrac{x^\\var{(n+m)/p}}{\\sqrt[\\var{q}]{x}\\sqrt[\\var{2q}]{x^\\var{q}}} \\end{split}\\]

\n

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To simplify the denominator, we want to apply rule 2, then rule 3, and then rule 1:

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\\[ \\begin{split} \\dfrac{x^\\var{(n+m)/p}}{\\sqrt[\\var{q}]{x}\\sqrt[\\var{2q}]{x^\\var{q}}} &\\,= \\dfrac{x^\\var{(n+m)/p}}{x^{1/\\var{q}}\\left(x^\\var{q}\\right)^{1/\\var{2q}}} \\\\\\\\ &\\,=\\dfrac{x^\\var{(n+m)/p}}{x^{1/\\var{q}} x^{1/2}}\\\\\\\\ &\\,=\\dfrac{x^\\var{(n+m)/p}}{x^\\simplify[fractionNumbers]{{1/q+1/2}}}.\\end{split} \\]

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Finally, applying rule 4 and simplifying, 

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\\[ \\begin{split} \\dfrac{x^\\var{(n+m)/p}}{x^\\simplify[fractionNumbers]{{1/q+1/2}}} &\\,= x^{\\var{(n+m)/p}-\\simplify[fractionNumbers]{{1/q+1/2}}} \\\\ &\\,= x^{\\simplify[fractionNumbers]{{(n+m)/p-(1/q+1/2)}}}. \\end{split}\\]

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Therefore,

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\\[ \\dfrac{\\sqrt[\\var{p}]{x^\\var{n}x^\\var{m}}}{\\sqrt[\\var{q}]{x}\\sqrt[\\var{2q}]{x^\\var{q}}} = x^{\\simplify[fractionNumbers]{{(n+m)/p-(1/q+1/2)}}}. \\]

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