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Adding and subtracting vectors of random size, including resolving brackets. Advice (i.e. solution) has conditional visibility to show only the correct size.

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Let \\(u=\\var{u}\\), \\(v=\\var{v}\\) and \\(w=\\var{w}\\).

", "advice": "

We add and subtract vectors entry by entry.

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Part a)

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\\[\\simplify[unitFactor]{v+{sign1}w}=\\begin{pmatrix}\\simplify[]{{v[0]}+{sign1*w[0]}} \\\\ \\simplify[]{{v[1]}+{sign1*w[1]}}  \\end{pmatrix} = \\var{v+sign1*w}\\]

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\\[\\simplify[unitFactor]{v+{sign1}w}=\\begin{pmatrix}\\simplify[]{{v[0]}+{sign1*w[0]}} \\\\ \\simplify[]{{v[1]}+{sign1*w[1]}} \\\\\\simplify[]{{v[2]}+{sign1*w[2]}}  \\end{pmatrix} = \\var{v+sign1*w}\\]

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\\[\\simplify[unitFactor]{v+{sign1}w}=\\begin{pmatrix}\\simplify[]{{v[0]}+{sign1*w[0]}} \\\\ \\simplify[]{{v[1]}+{sign1*w[1]}} \\\\\\simplify[]{{v[2]}+{sign1*w[2]}} \\\\\\simplify[]{{v[3]}+{sign1*w[3]}} \\end{pmatrix} = \\var{v+sign1*w}\\]

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Part b)

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\\[v -(\\simplify[unitFactor,!expandBrackets]{u+{sign2}*w})=\\begin{pmatrix}\\simplify[]{{v[0]}-({u[0]}+{sign2*w[0]})} \\\\ \\simplify[]{{v[1]}-({u[1]}+{sign2*w[1]})} \\end{pmatrix}=\\var{v-(u+sign2*w)} \\]

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\\[v -(\\simplify[unitFactor,!expandBrackets]{u+{sign2}*w})=\\begin{pmatrix}\\simplify[]{{v[0]}-({u[0]}+{sign2*w[0]})} \\\\ \\simplify[]{{v[1]}-({u[1]}+{sign2*w[1]})} \\\\\\simplify[]{{v[2]}-({u[2]}+{sign2*w[2]})} \\end{pmatrix}=\\var{v-(u+sign2*w)} \\]

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\\[v -(\\simplify[unitFactor,!expandBrackets]{u+{sign2}*w})=\\begin{pmatrix}\\simplify[]{{v[0]}-({u[0]}+{sign2*w[0]})} \\\\ \\simplify[]{{v[1]}-({u[1]}+{sign2*w[1]})} \\\\\\simplify[]{{v[2]}-({u[2]}+{sign2*w[2]})} \\\\\\simplify[]{{v[3]}-({u[3]}+{sign2*w[3]})} \\end{pmatrix}=\\var{v-(u+sign2*w)} \\]

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size of the vectors

", "templateType": "anything"}, "v": {"name": "v", "group": "Ungrouped variables", "definition": "vector((repeat(random(-5..5),rows)))", "description": "

randomly generated vector of random size.

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randomly generated vector of same size as v

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randomly generated vector of same size as v

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randomly generated sign

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Calculate \\(\\simplify{v + {sign1}*w}=\\) [[0]].

\n

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Calculate \\(v -(\\simplify[unitFactor,!expandBrackets]{u+{sign2}*w})=\\) [[0]].

\n

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