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Calculating the derivative of a function of the form $\\frac{ax^n+bx}{ax^n-bx}$ using the quotient rule.

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Find the derivative of \\[ \\simplify{y=({a}x^{n}+{b}x)/({a}x^{n}-{b}x)}. \\]

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If we have a function of the form $y=\\tfrac{u(x)}{v(x)}$, to calculate its derivative we need to use the quotient rule:

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\\[ \\dfrac{dy}{dx} = \\dfrac{v(x) \\times \\frac{du}{dx} - u(x) \\times\\frac{dv}{dx}}{[v(x)]^2}\\,.\\]

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This can be split up into steps:

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  1. Identify the functions $u(x)$ and $v(x)$;
  2. \n
  3. Calculate their derivatives $\\tfrac{du}{dx}$ and $\\tfrac{dv}{dx}$;
  4. \n
  5. Substitute these into the formula for the quotient rule to obtain an expression for $\\tfrac{dy}{dx}$;
  6. \n
  7. Simplify $\\tfrac{dy}{dx}$ where possible.
  8. \n
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Following this process, we must first identify $u(x)$ and $v(x)$.

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As \\[ \\simplify{y=({a}x^{n}+{b}x)/({a}x^{n}-{b}x)}, \\]

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let \\[ u(x) = \\simplify{{a}x^{n}+{b}x} \\quad \\text{and} \\quad v(x)=\\simplify{{a}x^{n}-{b}x}.\\]

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Next, we need to find the derivatives, $\\tfrac{du}{dx}$ and $\\tfrac{dv}{dx}$:

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\\[ \\dfrac{du}{dx} = \\simplify{{a*n}x^{n-1}+{b}}\\quad \\text{and} \\quad\\dfrac{dv}{dx}=\\simplify{{a*n}x^{n-1}-{b}}.\\]

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Substituting these results into the quotient rule formula we can obtain an expression for $\\tfrac{dy}{dx}$:

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\\[ \\begin{split} \\dfrac{dy}{dx} &\\,= \\dfrac{v(x) \\times \\frac{du}{dx} - u(x) \\times\\frac{dv}{dx}}{[v(x)]^2} \\\\ \\\\&\\,=\\dfrac{(\\simplify{{a}x^{n}-{b}x}) \\times (\\simplify{{a*n}x^{n-1}+{b}}) - (\\simplify{{a}x^{n}+{b}}) \\times (\\simplify{{n*a}x^{n-1}-{b}})}{\\simplify{({a}x^{n}-{b}x)^2}}.  \\end{split}\\]

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Simplifying,

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\\[ \\begin{split} \\dfrac{dy}{dx} &\\,= \\dfrac{\\simplify{({a}x^{n}-{b}x)({a*n}x^{n-1}+{b})-({a}x^{n}+{b})({n*a}x^{n-1}-{b})}}{\\simplify{({a}x^{n}-{b}x)^2}} \\\\ \\\\ &\\,=\\dfrac{\\simplify[all,!cancelTerms,!collectNumbers]{{n*a^2}x^{2*n-1}+{a*b}x^{n}-{n*a*b}x^{n}-{b^2}x-{n*a^2}x^{2*n-1}+{a*b}x^{n}-{n*a*b}x^{n}+{b^2}x}}{\\simplify{({a}x^{n}-{b}x)^2}} \\\\ \\\\ &\\,=\\dfrac{\\simplify{{2*a*b-2*n*a*b}x^{n}}}{\\simplify{({a}x^{n}-{b}x)^2}}. \\end{split} \\]

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$\\dfrac{dy}{dx}=$[[0]] 

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