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Calculating the integral of a function of the form $ax^b$ using a table of integrals. 

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Using the Table of Integrals/Antiderivatives, calculate the integral of $f(x)=\\simplify{{a}x^{b}}$.

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From the Table of Integrals we see that a function of the form \\[ f(x)=x^n \\] has the integral \\[ \\int x^n dx  =  \\frac{x^{n+1}}{n+1}+ c,\\]

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and \\[\\int kf(x) dx = k \\int f(x) dx.\\]

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So, for the function

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\\[ f(x)=\\simplify{{a}x^{b}}, \\]

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the integral  is

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\\[ \\simplify{int({a}x^{b},x)} = \\simplify{{a}int(x^{b},x)} = \\simplify[all,fractionNumbers]{{a}x^{b+1}/{b+1}}+c.\\]

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You forgot the constant of integration.

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