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Integrating an exponential function of the form $ae^{bx}$ using a table of integrals / anti-derivatives.

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Find the integral of $f(x)=\\var{a}e^{\\simplify{{b}x}}$

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From the Table of Integrals we see that a function of the form \\[ f(x)= e^{mx} \\] has the integral \\[ \\int e^{mx} dx  = \\frac{1}{m}e^{mx}+c,\\]

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and \\[ \\int kf(x) \\,dx = k \\int f(x) \\, dx.\\]

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So, for the function

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\\[f(x)=\\simplify{{a}e^({b}x)},\\]

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the integral is

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\\[ \\begin{split} \\int\\simplify{{a}e^({b}x)} dx \\,= \\simplify[unitFactor]{{a}int(e^({b}x),x)} =\\simplify[unitFactor,fractionNumbers]{{a/b} e^({b}x)+c}. \\end{split}  \\]

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[[0]]

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You forgot the constant of integration.

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