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Solving a differential equation of the form $\\frac{dy}{dx}=\\frac{ax^n}{y}$ using separation of variables.

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Solve the differential equation \\[ \\frac{dy}{dx}=\\frac{\\var{a}x^\\var{n}}{y}.\\]

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If we have a differential equation of the form \\[ \\frac{dy}{dx} = f(x) g(y),\\] we are able to find a solution to this equation using the method Separation of Variables.

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We can rewrite the above equation in the form \\[ \\frac{1}{g(y)} \\frac{dy}{dx} = f(x).\\]

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If we then integrate with respect to $x$: 

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\\[ \\begin{split} &\\int \\frac{1}{g(y)} &\\frac{dy}{dx} dx = \\int f(x) dx, \\\\\\\\ \\implies &\\int \\frac{1}{g(y)} &dy = \\int f(x) dx.  \\end{split} \\]

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Integrating both sides, we can write $y$ as a function of $x$. 

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Following this method for $\\frac{dy}{dx}=\\frac{\\var{a}x^\\var{n}}{y}$:

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\\[\\frac{dy}{dx}=\\frac{\\var{a}x^\\var{n}}{y}\\]

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\\[ \\begin{split} &\\frac{dy}{dx}=\\frac{\\var{a}x^\\var{n}}{y} \\\\ \\implies  y\\,& \\frac{dy}{dx} = \\simplify{{a}x^{n}}. \\end{split} \\]

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Integrating both sides with respect to $x$:

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\\[ \\begin{split}  \\int  y \\, \\frac{dy}{dx}\\, dx &= \\int \\simplify{{a}x^{n}} \\, dx, \\\\ \\\\ \\implies \\int y \\,dy &= \\int\\simplify{{a}x^{n}} \\, dx.   \\end{split} \\]

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Taking the integral of both sides, we are able to find a solution to the differential equation:

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\\[ \\begin{split} \\int y \\,dy &=\\simplify{{a}x^{n}} \\, dx \\\\ \\frac{y^2}{2}&\\,= \\simplify{{a}x^{n+1}/{n+1} +c}, \\\\ y^2 &\\,= \\simplify{{2a}x^{n+1}/{n+1} + 2c} \\\\  y &\\,= \\pm\\sqrt{\\simplify{{2a}x^{n+1}/{n+1} + 2c}}.  \\end{split} \\]

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Note: You can also have the answer 

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\\[ y = \\pm \\sqrt{\\simplify{{2a}x^{n+1}/{n+1}+D}}, \\]

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where $D=2c$. This shows there is still a constant, but indicates it is different to the original constant of integration, $c$.

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