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Solving a differential equation of the form $\\frac{dy}{dx}=a \\cos(x) e^{-y}$ using separation of variables.

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Solve the differential equation \\[ \\frac{dy}{dx}=\\var{a}\\cos(x) e^{-y}.\\]

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If we have a differential equation of the form \\[ \\frac{dy}{dx} = f(x) g(y),\\] we are able to find a solution to this equation using the method Separation of Variables.

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We can rewrite the above equation in the form \\[ \\frac{1}{g(y)} \\frac{dy}{dx} = f(x).\\]

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If we then integrate with respect to $x$: 

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\\[ \\begin{split} &\\int \\frac{1}{g(y)} &\\frac{dy}{dx} dx = \\int f(x) dx, \\\\\\\\ \\implies &\\int \\frac{1}{g(y)} &dy = \\int f(x) dx.  \\end{split} \\]

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Integrating both sides, we can write $y$ as a function of $x$. 

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Following this method for $\\frac{dy}{dx}=\\var{a}\\cos(x) e^{-y}$:

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\\[ \\begin{split} &\\frac{dy}{dx}=\\var{a}\\cos(x) e^{-y}, \\\\\\\\ \\implies  \\frac{1}{e^{-y}}& \\frac{dy}{dx} = \\var{a}\\cos(x), \\\\\\\\ \\implies  e^{y}& \\frac{dy}{dx} = \\var{a}\\cos(x). \\end{split} \\]

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Integrating both sides with respect to $x$:

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\\[ \\begin{split} & \\int  e^y \\frac{dy}{dx} dx = \\int \\var{a}\\cos(x) \\, dx, \\\\ \\\\ \\implies &\\int e^y dy = \\int \\var{a} \\cos(x) \\, dx.   \\end{split} \\]

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Taking the integral of both sides, we are able to find a solution to the differential equation:

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\\[ \\begin{split} \\int  e^y dy &\\,= \\int \\var{a} \\cos(x) \\, dx, \\\\ e^y &\\,= \\simplify{{a}sin(x) +c}, \\\\  y&\\,=\\ln\\left(\\simplify{{a}sin(x) +c}\\right).  \\end{split} \\]

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$y=\\,$[[0]]

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