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Tuliskan jawaban anda pada kotak yang tersedia. Jawaban yang diterima berupa bilangan bulat atau pecahan biasa.

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{c_1} < {a}$x$+{b} < {c_2}

\n

$\\Leftrightarrow$ {c_1}-{b} < {a}$x$ < {c_2}-{b}

\n

$\\Leftrightarrow$ ({c_1}-{b})/{a} < $x$ < ({c_2}-{b})/{a}

\n

$\\Leftrightarrow$ {d_1} < $x$ < {d_2}.

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Solusi dari pertidaksamaan {c_1} < {a}$x$+{b} < {c_2} adalah [[0]] < $x$ < [[1]].

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