// Numbas version: finer_feedback_settings {"name": "Functions: Transformations (Combinations) 1d", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "Functions: Transformations (Combinations) 1d", "tags": [], "metadata": {"description": "

Finding the transformation of a linear function $f(x)=mx+c$ to $f(ax)+b$.

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If $f(x)=\\simplify{{m}x+{c}}$, what is $\\simplify{f({a}x)+{b}}$?

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To make the transformation from $f(x)=\\simplify{{m}x+{c}}$ to $\\simplify{f({a}x)+{b}}$, we need to replace the $x$-terms in $f(x)$ with $\\simplify{{a}x}$, and then {aors} $\\var{b}$ {torf} this function:

\n

{advice}

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\\\\[ \\\\begin{split} \\\\simplify{f({a}x)+{b}} &\\\\,= \\\\simplify[!expandBrackets,!collectNumbers]{({m}({a}x)+{c})+{b}} \\\\\\\\ &\\\\,=\\\\simplify{{m*a}x+{c+b}}. \\\\end{split} \\\\]

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\\\\[ \\\\begin{split} \\\\simplify{f({a}x)+{b}} &\\\\,= \\\\simplify[!expandBrackets,!collectNumbers]{({m}({a}x)+{c})+{b}} \\\\\\\\ &\\\\,=\\\\simplify{{m*a}x+{c+b}} \\\\\\\\ &\\\\,=\\\\simplify{{simp}({(m*a)/simp}x+{(c+b)/simp})}. \\\\end{split} \\\\]

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$\\simplify{f({a}x)+{b}}=$[[0]]

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