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Finding the transformation of a function of the form $f(x)=\\frac{mx+c}{x^2-d}$ to $af(x+b)$.

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If $f(x)=\\simplify{({m}x+{c})/(x^2-{d})}$ for $x\\neq \\simplify{sqrt({d})}$, what is $\\simplify{{a}f(x+{b})}$?

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To make the transformation from $f(x)=\\simplify{({m}x+{c})/(x^2-{d})}$ to $\\simplify{{a}f(x+{b})}$, we need to replace the $x$-terms in $f(x)$ with $\\simplify{x+{b}}$ and then multiply that function by $\\var{a}$:

\n

{advice}

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\\\\[ \\\\begin{split} \\\\simplify{{a}f(x+{b})} &\\\\,= \\\\var{a}\\\\left(\\\\simplify[unitFactor]{({m}(x+{b})+{c})/((x+{b})^2-{d})}\\\\right) \\\\\\\\ &\\\\,= \\\\var{a}\\\\left(\\\\simplify[unitFactor,!collectNumbers]{({m}x+{m*b}+{c})/((x^2+{2*b}x+{b^2})-{d})}\\\\right) \\\\\\\\&\\\\,= \\\\simplify[unitFactor]{{a}({m}x+{m*b+c})/(x^2+{2*b}x+{b^2-d})}. \\\\end{split} \\\\]

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\\\\[ \\\\begin{split} \\\\simplify{{a}f(x+{b})} &\\\\,= \\\\var{a}\\\\left(\\\\simplify[unitFactor]{({m}(x+{b})+{c})/((x+{b})^2-{d})}\\\\right) \\\\\\\\ &\\\\,= \\\\var{a}\\\\left(\\\\simplify[unitFactor,!collectNumbers]{({m}x+{m*b}+{c})/((x^2+{2*b}x+{b^2})-{d})}\\\\right) \\\\\\\\&\\\\,= \\\\simplify[unitFactor]{{a}({m}x+{m*b+c})/(x^2+{2*b}x+{b^2-d})}\\\\\\\\&\\\\,= \\\\simplify[unitFactor]{{a*simp}({m/simp}x+{(m*b+c)/simp})/(x^2+{2*b}x+{b^2-d})}. \\\\end{split} \\\\]

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$\\simplify{{a}f(x+{b})}=$[[0]]

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