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Students are given a diagram with 2 triangles. They are given 2 randomised lengths, and a randomised angle of depression.

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They need to compute an angle by subtracting the angle of depression from 90°. Then they need to use the sine rule to calculate a second angle. Then they need to use the alternate angles on parallel lines theorem to work out a third angle. They use these to calculate a third angle, which they use in the right-angle triangle with the sine ratio to compute the third side. They then use the cos ratio to compute the length of the third side.

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A person standing on the top of a building at $J$ looks down to a garden on the ground at point $M$. The angle of depression from $J$ to $M$ is $\\var{aod}$°. There is a window in the building at $K$, $\\var{JK}$ metres below $J$. The distance from $M$ to $K$ is $\\var{KM}$ metres.

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not to scale

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", "advice": "

$\\angle MJK = 90° - \\var{aod}° = \\var{aMJK}°$

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In $\\triangle JKM$, by the sine rule, $\\frac{JK}{\\sin (\\angle M)}=\\frac{KM}{\\sin (\\angle J)}$

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$\\frac{\\var{JK}}{\\sin (\\angle M)}=\\frac{\\var{KM}}{\\sin \\var{aMJK}°}$

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$\\angle M = \\angle JMK = \\var{aJMK}°$

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Now $\\angle JML = \\var{aod}$° (alternate angles on parallel lines)

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So $\\angle KML = \\angle JML - \\angle JMK = \\var{aod}° - \\var{aJMK}° = \\var{aKML}° $

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The angle of elevation from $M$ to $K$ is $\\var{aKML}° $.

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$\\triangle KML$ is a right-angle triangle, and $\\angle KML = 90°$

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So to find $KL$ we can use the sine ratio: $\\sin(angle)=\\frac{opposite}{hypotenuse}$

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$\\sin(\\var{aKML})° = \\frac{KL}{\\var{KM}}$

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$KL = \\var{KM} \\times \\sin(\\var{aKML}°) = \\var{KL}$ m

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The distance from the ground to $K$ is $\\var{KL}$ m.

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To find $LM$ we can use the cosine ratio: $\\cos(angle)=\\frac{adjacent}{hypotenuse}$

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$\\cos(\\var{aKML})° = \\frac{LM}{\\var{KM}}$

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$LM = \\var{KM} \\times \\cos(\\var{aKML}°) = \\var{LM}$ m

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The distance from the pond to the building is $\\var{LM}$ m.

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Calculate the angle of elevation from $M$ to $K$. Give your answer to the nearest degree.

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What is the distance, in metres, from the ground (at $L$) to the window (at $K$)? Give your answer to the nearest metre.

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How far is it, in metres, from the building to the garden (i.e. what is the length of $LM$)?

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Give your answer to the nearest metre.

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