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Finding the transformation of a function of the form $f(x)=\\frac{mx+c}{x^2-d}$ to $f(ax)+b$.

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If $f(x)=\\simplify{({m}x+{c})/(x^2-{d})}$ for $x\\neq \\simplify{sqrt({d})}$, what is $\\simplify{f({a}x)+{b}}$?

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To make the transformation from $f(x)=\\simplify{({m}x+{c})/(x^2-{d})}$ to $\\simplify{f({a}x)+{b}}$, we need to replace the $x$-terms in $f(x)$ with $\\simplify{{a}x}$ and then {aors} $\\var{abs(b)}$:

\n

{advice}

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\\\\[ \\\\begin{split} \\\\simplify{f({a}x)+{b}} &\\\\,= \\\\simplify[unitFactor,!expandBrackets]{({m}({a}x)+{c})/(({a}x)^2-{d})+{b}} \\\\\\\\ &\\\\,=\\\\simplify[unitFactor,!expandBrackets]{({m*a}x+{c})/({facden}({a^2/facden}x^2-{d/facden}))+{b}}. \\\\end{split} \\\\]

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\\\\[ \\\\begin{split} \\\\simplify{f({a}x)+{b}} &\\\\,= \\\\simplify[unitFactor,!expandBrackets]{({m}({a}x)+{c})/(({a}x)^2-{d})+{b}} \\\\\\\\ &\\\\,=\\\\simplify[unitFactor,!expandBrackets]{({m*a}x+{c})/({a^2}x^2-{d})+{b}}\\\\\\\\ &\\\\,=\\\\simplify[unitFactor,!expandBrackets]{({simp}({m*a/simp}x+{c/simp}))/({facden}({(a^2)/facden}x^2-{d/facden}))+{b}}. \\\\end{split} \\\\]

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\\\\[ \\\\begin{split} \\\\simplify{f({a}x)+{b}} &\\\\,= \\\\simplify[unitFactor,!expandBrackets]{({m}({a}x)+{c})/(({a}x)^2-{d})+{b}} \\\\\\\\ &\\\\,=\\\\simplify[unitFactor,!expandBrackets]{({m*a}x+{c})/({a^2}x^2-{d})+{b}}\\\\\\\\ &\\\\,=\\\\simplify[unitFactor,!expandBrackets]{({simp}({m*a/simp}x+{c/simp}))/({facden}({(a^2)/facden}x^2-{d/facden}))+{b}} \\\\\\\\ &\\\\,=\\\\simplify[all,unitFactor,!expandBrackets]{({simp/fac}({m*a/simp}x+{c/simp}))/({facden/fac}({(a^2)/facden}x^2-{d/facden}))+{b}}. \\\\end{split} \\\\]

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$\\simplify{f({a}x)+{b}}=$[[0]]

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