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Multiplication and addition of complex numbers. Four parts.

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Original: https://numbas.mathcentre.ac.uk/question/11785/arithmetics-of-complex-numbers-ii/ by Newcastle University Mathematics and Statistics

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Translated to German.

", "licence": "Creative Commons Attribution 4.0 International"}, "statement": "

Schreiben Sie die folgenden komplexen Zahlen in der Form $a+bi\\;$ für reelle Zahlen $a$ und $b$.

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Geben Sie alle Zahlen als Bruchzahlen oder als ganze Zahlen an.

", "advice": "

a)

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Die Lösung ist

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$\\simplify[std]{{e6*i}}(\\simplify[std]{{a}})=\\simplify[std]{{a*e6*i}}$

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b)

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$\\simplify[std]{{a}*{z4}={a*z4}}$

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c)

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\\[ \\begin{eqnarray*} \\simplify[std,!otherNumbers]{{a}*({a3} + {b3} * i + {c3} * i ^ 2 + {d3} * i ^ 3)}&=&\\simplify[std]{{a}*{a3 + b3 * i + c3 * i ^ 2 + d3 * i ^ 3}}\\\\ &=&\\simplify[std]{{a*(a3 + b3 * i + c3 * i ^ 2 + d3 * i ^ 3)}} \\end{eqnarray*} \\]

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d)

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Rechnen Sie in mehreren Schritten:

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\\[ \\begin{eqnarray*} (\\var{a})(\\var{z1})(\\var{z3})&=&((\\var{a})(\\var{z1}))(\\var{z3})\\\\ &=&(\\var{a*(z1)})(\\var{z3})\\\\ &=&\\var{a*(z1)*(z3)} \\end{eqnarray*} \\]

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$\\var{e6*i}(\\simplify[std]{{a}})\\;=\\;$[[0]].

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$(\\simplify[std]{{a}})(\\simplify[std]{{z4}})\\;=\\;$[[0]].

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$\\simplify[std,!otherNumbers]{{a}*({a3} + {b3} * i + {c3} * i ^ 2 + {d3} * i ^ 3)}\\;=\\;$[[0]].

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$(\\simplify[std]{{a}})(\\simplify[std]{ {z1}})(\\simplify[std]{ {z3}})\\;=\\;$[[0]].

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