// Numbas version: exam_results_page_options {"name": "Trigonometry: Sine Rule 2", "extensions": ["geogebra"], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "Trigonometry: Sine Rule 2", "tags": [], "metadata": {"description": "

Given two side-lengths and an angle of a triangle, use the sine rule to calculate an unknown angle.

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Find the angle $A$:

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{geogebra_applet('https://www.geogebra.org/m/d4yzdkwg',defs)}

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Since we know two side-lengths and one of the their opposite angles, we can use the sine rule to find the unknown angle, $A$. The sine rules states:

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\\[ \\frac{\\sin(A)}{a} = \\frac{\\sin(B)}{b} = \\frac{\\sin(C)}{c}, \\]

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where $a$, $b$, and $c$ are the side-lengths, and $A$, $B$, and $C$ are the angles opposite the side with the same letter:

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{geogebra_applet('https://www.geogebra.org/m/fjh4qce5')}

\n

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So, for the triangle

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{geogebra_applet('https://www.geogebra.org/m/d4yzdkwg',defs)}

\n

we know that side $a=\\var{sidear}$, side $b=\\var{sidebr}$, and angle $B=\\var{anglebr}^\\circ$. Substituting these values into the sine rule we can calculate the angle of $A$:

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\\[ \\begin{split} \\frac{\\sin(A)}{\\var{sidear}}&\\,=\\frac{\\sin(\\var{anglebr})}{\\var{sidebr}}\\\\\\\\ \\sin(A) &\\,= \\frac{\\var{sidear}\\times\\sin(\\var{anglebr})}{\\var{sidebr}}\\\\\\\\  A &\\,= \\sin^{-1}\\left(\\frac{\\var{sidear}\\times\\sin(\\var{anglebr})}{\\var{sidebr}}\\right) \\\\ \\\\&\\,=\\var{aaar}\\,^\\circ \\text{ (2 d.p.).}\\end{split} \\]

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$A=$[[0]] $^\\circ$

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(Give your answer to 2 decimal places when necessary)

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