// Numbas version: finer_feedback_settings {"name": "Partial Fractions: Proper Fractions 5b", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "Partial Fractions: Proper Fractions 5b", "tags": [], "metadata": {"description": "

Rewrite the expression $\\frac{n}{(x+a)(x+b)^2}$ as partial fractions in the form $\\frac{A}{x+a}+\\frac{B}{x+b}+\\frac{C}{(x+b)^2}$.

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Rewrite the following expression as partial fractions:

\n

\\[ \\simplify{{n}/((x+{a})(x+{b})^2)}. \\]

", "advice": "

To express \\[ \\simplify{{n}/((x+{a})(x+{b})^2)} \\] as partial fractions, we want to set this equal to the sum of three fractions with denominators $\\simplify{x+{a}}$, $\\simplify{x+{b}}$, and $\\simplify{(x+{b})^2}$. Since we have a distinct linear factor and a repeated linear factor, this tells us that the numerators will be constants, which we will call $A$, $B$, and $C$:

\n

\\[ \\simplify{{n}/((x+{a})(x+{b})^2)} = \\simplify{A/(x+{a}) + B/(x+{b})+ C/(x+{b})^2}.\\]

\n

To find the values of $A$, $B$, and $C$, we want to first multiply this equation by the denominator of the left-hand side. This gives

\n

\\[ \\simplify{{n}=A(x+{b})^2+B(x+{a})(x+{b}) + C(x+{a})}.\\]

\n

(Note: To find $A$, $B$, and $C$, we will use a combination of choosing suitable values of $x$ to eliminate terms, and equating coefficients. It can be solved by only equating coefficients, but this is a more efficient process.)

\n

\n

To find $A$, we can eliminate $B$ and $C$ by setting $x=\\var{-a}$:

\n

\\[ \\simplify{{n}=A{(b-a)^2}} \\implies A=\\simplify[fractionNumbers]{{Asol}}.\\]

\n

To find $C$, we can eliminate $A$ and $B$ by setting $x=\\var{-b}$:

\n

\\[ \\simplify{{n}=C{(a-b)}} \\implies C=\\simplify[fractionNumbers]{{Csol}}.\\]

\n

Finally, by equating coefficients of the $x^2$-terms we can find $B$:

\n

\\[ (x^2): \\quad 0 = \\simplify{A+B} \\implies B=-A. \\]

\n

Therefore, \\[ B=\\simplify[fractionNumbers]{{Bsol}}, \\]

\n

and

\n

{check}

\n

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\\\\[ \\\\simplify{{n}/((x+{a})(x+{b})^2)} = \\\\simplify{{Asol}/(x+{a})+{Bsol}/(x+{b})+{Csol}/(x+{b})^2}.\\\\]

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\\\\[ \\\\simplify{{n}/((x+{a})(x+{b})^2)} = \\\\simplify[all,fractionNumbers]{{n}/({(b-a)^2}(x+{a}))-{n}/({(b-a)^2}(x+{b}))+{n}/({(a-b)}(x+{b})^2)}.\\\\]

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