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Rewrite the expression $\\frac{cx+d}{(x+a)^2}$ as partial fractions in the form $\\frac{A}{x+a}+\\frac{B}{(x+a)^2}$.

", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "

Rewrite the following expression as partial fractions:

\n

\\[ \\simplify{({c}x+{d})/(x+{a})^2} .\\]

", "advice": "

To express\\[ \\simplify{({c}x+{d})/(x+{a})^2} \\] as partial fractions, because we have a repeated linear factor we want to set this equal to the sum of 2 fractions with denominators $\\simplify{x+{a}}$ and $\\simplify{(x+{a})^2}$. The numerators will be constants, which we will call $A$ and $B$:

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\\[ \\simplify{({c}x+{d})/((x+{a})^2)} = \\simplify{A/(x+{a}) + B/(x+{a})^2}.\\]

\n

To find the values of $A$ and $B$, we want to first multiply this equation by the denominator of the left-hand side. This gives

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\\[ \\simplify{{c}x+{d}=A(x+{a})+B}.\\]

\n

\n

By comparing the coefficients of the $x$-terms and the constant terms we can form a pair of simultaneous equations to find $A$ and $B$:

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\\[ \\begin{split} \\simplify{{c}x+{d}} &\\,= \\simplify{A(x+{a})+B} \\\\ &\\,= \\simplify{A*x+{a}A+B}. \\end{split} \\]

\n

\\[ \\begin{split}&(x):\\quad \\var{c} &\\,= \\simplify{A} \\\\ &(c):\\quad \\var{d} &\\,= \\simplify{{a}A+B} .\\end{split} \\]

\n

Hence,

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\\[A=\\var{c},\\,B=\\simplify{{d-a*c}}, \\]

\n

and

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\\[ \\simplify{({c}x+{d})/((x+{a})^2)} = \\simplify{{c}/(x+{a}) + {d-a*c}/(x+{a})^2}\\]

\n

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