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Nach Nikomachos: Ermitteln der 5. Proportion

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Nach Nikomachos stehen drei Zahlen $a<b<c$ dann in der \"fünften Proportion\", wenn die mittlere Zahl sich zur kleinere Zahl verhält, wie sich deren Differenz zur Differenz der größeren Zahl und der mittleren Zahl verhält.

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a) Es gilt: $b:a=(b-a):(c-a)$

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b) Durch probieren (oder auflösen der Gleichung oben) kann man mehrere Lösungen finden, eine mögliche Lösung ist $2, 4, 5$, sowie alle ganzzahligen Vielfachen dieser Lösung.

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Beschreiben Sie die Proportion durch eine Gleichung in den Variablen $a,b,c$:

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$\\Big($[[0]]$\\Big):\\Big($[[1]]$\\Big)=\\Big($[[2]]$\\Big):\\Big($[[3]]$\\Big)$

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Finden Sie drei natürliche Zahlen $a<b<c$, die in fünfter Proportion stehen:

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{app}

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