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Objetivo: Resolver ecuaciones de segundo grado de la forma $x^2+bx+c=0$ que se pueden factorizar.

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3) Al resolver la ecuación de segundo grado $x^2+4x+3=0$ se obtiene que sus raíces son:

A) $-3$ y $-1$

B) $3$ y $1$

C) $-2$ y $2$

D) $2$ y $-1$

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Para resolver la ecuación de segundo grado $x^2+4x+3=0$ debemos seguir los siguientes pasos:

\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n

\n $x^2+4x+3=0$ \n	\n Paso 1: Para factorizar debemos pensar en dos números $a$ y $b$ que multiplicados sean igual a $3$ y sumados sean igual a $4$. Estos números son $a=$[[0]] y $b=$[[1]]. (Aquí diremos que $a$ es mayor que $b$) \n
$(x+$[[2]]$)\\cdot(x+$[[3]]$)=0$	\n Paso 2: De los números obtenidos en el paso 1 obtenemos los factores $(x+$[[2]]$)$ y $(x+$[[3]]$)$ que usaremos para la factorización. \n
$x+$[[4]]$=0$ y $x+$[[5]]$=0$	Paso 3: Como $(x+$[[2]]$)$ y $(x+$[[3]]$)$ multiplicadas son igual a $0$, por propiedad dos números multiplicados dan $0$ si uno de los dos es $0$, obteniendo así las ecuaciones $x+$[[4]]$=0$ y $x+$[[5]]$=0$.
$x=$[[6]] y $x=$[[7]]	Paso 4: Se resuelven las ecuaciones del paso 3 obteniendo que $x=$[[6]] y $x=$[[7]]

La respuesta correcta es la alternativa: [[8]]

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