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3)  En una urna hay 6 bolitas blancas y 3 azules  ¿Cuál es la probabilidad de sacar al azar ambas blancas sin reposición?

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     A)  $\\Large \\frac{1}{2}$

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     B)  $\\Large \\frac{5}{8}$

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     C)  $\\Large \\frac{2}{3}$

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     D)  $\\Large \\frac{5}{12}$

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Para determinar la probabilidad de sacar dos bolitas blancas sin reposición, debemos seguir los siguientes pasos.

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                                                  [[0]]

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$P(1°$ bolita blanca$)=$  ______ 

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                                                 [[1]]

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Paso 1: Calcular la probabilidad de que la primera bolita sea blanca.
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                                                [[2]]

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$P(2°$ bolita blanca$)=$  ______ 

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                                                 [[3]]

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Paso 2: Calcular la probabilidad de que la primera bolita sea blanca. Recuerda que se debe eliminar una bolita blanca (ya que no se repone la bolita al ser sacada) y del total de bolitas también se elimina una.

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                                                      [[0]]  [[2]]

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$P(2 $ blancas sin reponer$)= $ ______ $\\cdot$ ______  $=$

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                                                       [[1]]  [[3]]

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       [[4]]

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$=$ ______

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       [[5]]

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Paso 3: Como ambos sucesos ocurren uno después del otro, debemos multiplicar las probabilidades del paso 1 y 2.
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                                                            [[6]]

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$P(2$ blancas sin reponer$)=$ ______

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                                                            [[7]]

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Paso 4: Se simplifica el valor obtenido en el paso 3.
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Por tanto, la respuesta correcta es: [[8]]

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