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5) El resultado de $\\log_2{64}+\\log_5{125}$, es:
\nA) $6$
\nB) $7$
\nC) $8$
\nD) $9$
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\n$\\Large \\log_b{a}=c \\Leftrightarrow b^a=c$
\nPaso 1: Determinar el valor de $\\log_2{64}=x$, por definición esto es igual a: | \n
\n $x$ \n$\\Large \\log_2{64}=x \\Leftrightarrow$ [[0]] $=$ [[1]] \nPor lo tanto, debemos determinar [[0]] elevado a cuanto es igual a [[1]], obteniendo que $x=$[[2]] \n | \n
Paso 2: Determinar el valor de $\\log_5{125}=y$, por definición esto es igual a: | \n
\n $y$ \n$\\Large \\log_5{125}=x \\Leftrightarrow$ [[3]] $=$ [[4]] \nPor lo tanto, debemos determinar [[3]] elevado a cuanto es igual a [[4]], obteniendo que $y=$[[5]] \n | \n
\n Paso 3: Ahora sumamos los valores obtenidos en el paso 2 y 3, concluyendo que: \n$\\log_2{64}+\\log_5{125}=$[[2]]$+$[[5]]$=$[[6]] \n | \n
Por tanto, la respuesta correcta es: [[7]]
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