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5) Determine las coordenadas de los puntos de corte del eje X de la función $f(x)=x^2+7x+12$.
\nA) $(-4,0)$ y $(3,0)$
\nB) $(4,0)$ y $(3,0)$
\nC) $(-4,0)$ y $(-3,0)$
\nD) $(4,0)$ y $(-3,0)$
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\nPaso 1: En la ecuación $f(x)=x^2+7x+12=0$, debemos primero pensar en dos números $a$ y $b$ que cumplan las siguientes condiciones, que multiplicados sean igual a 12 y sumados sean igual a 7, estos dos números son $a=$[[0]] y $b=$[[1]]. (Observación aquí $a>b$)
\nPaso 2: Con los valores $a=$[[0]] y $b=$[[1]], obtenemos la siguiente factorización:
\n$(x+a) \\cdot (x+b)=0$=$(x+$[[2]]$)\\cdot(x+$[[3]]$)=0$
\nPaso 3: Determinamos de la factorización las ecuaciones:
\n$x+a=0$ y $x+b=0$
\n$x+$[[4]]$=0$ y $x+$[[5]]$=0$
\nPaso 4: Despejamos las ecuaciones del paso 3, obteniendo que las coodenadas x de los puntos de corte del eje X son:
\n$x_1=$[[6]] y $x_2=$[[7]]
\nPaso 5: Las coordenadas de corte son $(x_1,0)=($[[8]] $,0)$ y $(x_2,0)=($[[9]] $,0)$
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