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5)  Determine las coordenadas de los puntos de corte del eje X de la función $f(x)=x^2+7x+12$.

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     A)    $(-4,0)$  y  $(3,0)$

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     B)    $(4,0)$  y  $(3,0)$

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     C)    $(-4,0)$  y  $(-3,0)$

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     D)    $(4,0)$  y  $(-3,0)$

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Para determinar los puntos de corte en el eje X debemos resolver la ecuación de segundo grado $f(x)=x^2+7x+12=0$, para ello realizaremos los siguientes pasos:

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Paso 1: En la ecuación $f(x)=x^2+7x+12=0$, debemos primero pensar en dos números $a$ y $b$ que cumplan las siguientes condiciones, que multiplicados sean igual a 12 y sumados sean igual a 7, estos dos números son $a=$[[0]]  y  $b=$[[1]]. (Observación aquí $a>b$)

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Paso 2: Con los valores $a=$[[0]]  y  $b=$[[1]], obtenemos la siguiente factorización:

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$(x+a) \\cdot (x+b)=0$=$(x+$[[2]]$)\\cdot(x+$[[3]]$)=0$

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Paso 3: Determinamos de la factorización las ecuaciones:

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$x+a=0$                 y                  $x+b=0$

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$x+$[[4]]$=0$                  y                 $x+$[[5]]$=0$

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Paso 4: Despejamos las ecuaciones del paso 3, obteniendo que las coodenadas de los puntos de corte del eje X son:

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$x_1=$[[6]]               y            $x_2=$[[7]]

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Paso 5: Las coordenadas de corte son $(x_1,0)=($[[8]] $,0)$  y   $(x_2,0)=($[[9]] $,0)$

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La respuesta es: [[0]]

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