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Misalkan \\( f(x) = \\displaystyle\\sum_{n=2}^{\\infty}  x^{n} \\) deret pangkat dengan himpunan kekonvergenan \\( |x|<1 \\). 

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\\( f\\left( \\dfrac{1}{\\var{a}} \\right) = \\)[[0]].

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Misalkan \\( g\\left( \\dfrac{1}{x} \\right)=xf''(x) \\).

\n

Maka nilai dari \\( g(\\var{a})= \\) [[0]].

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Himpunan kekonvergenan deret \\( g(x) \\) adalah $\\ldots$.

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Dengan menggunakan deret pangkat \\( g(x) \\), tentukan $\\displaystyle\\sum_{n=2}^\\infty \\dfrac{n(n-1)}{\\simplify{{a}+1}^n} =$ [[0]].

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