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Jika $P(u,v,w)=\\sqrt{u^2+v^2+w^2}$ dengan $u(x,y)=xe^y$, $v(x,y)=ye^x$, dan $w(x,y)=e^{xy}$. Jika $\\dfrac{\\partial P}{\\partial x}(0,\\var{a})+\\dfrac{\\partial P}{\\partial y}(0,\\var{a})=\\dfrac{a}{\\sqrt{\\var{a^2+1}}}$, maka nilai dari $a$ adalah $\\ldots$.

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