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Daerah \\( R \\) yang dibatasi oleh lintasan tertutup \\( C \\) akan mempunyai luas \\( A(R)=\\dfrac{1}{2}\\displaystyle\\oint_C (-y\\,dx+x\\,dy). \\) 

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Jika \\( C_1\\) menyatakan garis yang menghubungkan titik \\( (\\var{a},0) \\) ke titik \\( ({\\var{a+r}},\\var{b}) \\), maka \\( \\dfrac{1}{2}\\displaystyle\\int_{C_1} (-y\\,dx+x\\,dy) =\\) [[0]].

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Jika \\( C_2\\) menyatakan garis yang menghubungkan titik \\( ({\\var{a+r}},\\var{b}) \\) ke titik \\( (\\var{a},{\\var{a+r}}) \\), maka \\( \\dfrac{1}{2}\\displaystyle\\int_{C_2} (-y\\,dx+x\\,dy) =\\) [[1]].

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Jika \\( C_3\\) menyatakan garis yang menghubungkan titik \\( (\\var{a},{\\var{a+r}})  \\) ke titik  \\( (\\var{a},0) \\), maka \\( \\dfrac{1}{2}\\displaystyle\\int_{C_3} (-y\\,dx+x\\,dy) =\\) [[2]].

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Maka luas segitiga dengan titik sudut \\( (\\var{a},0) \\), \\( ({\\var{a+r}},\\var{b}) \\), dan \\( (\\var{a},{\\var{a+r}}) \\) adalah [[3]].

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Luas segilima dengan titik sudut \\( (\\var{a},0) \\), \\( ({\\var{a+r}},\\var{b}) \\), \\( (\\var{a},{\\var{a+r}}) \\), \\( (0,\\var{r+1}) \\), dan \\( (0,\\var{r}) \\) adalah \\(\\ldots\\).

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