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Diiberikan persamaan diferensial $x''-\\var{2*k}x'+\\var{k^2}x=(2t+\\var{k})e^{\\var{k}t}\\sec(t^2+\\var{k}t)$ dengan syarat awal $x(0)=1$ dan $x'(0)=2$.

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Jika solusi dari persamaan diferensial tersebut adalah $x(t)$, maka $x''(0)=\\ldots$.

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