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a) Line 1 assigns $x$ and line 2 assigns $y$ using $x$, therefore $y=\\var{{a}*{x}}$.
Line 3 is a calculation that uses $y$ but never reassigns any of the variables.
Line 4 then overwrites $x$ using $y$. Therefore $x=\\var{{a}*{b}*{x}}$.

\n

 b) The value of $z$ is the same as the value of $x$.

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What is the value of $x$?

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{b*a*x}

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{b + a*x + 2}

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{x}

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{b + 2}

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What is the value of $z$?

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{b*a*x}

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{b+a}

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{b}

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{a*x}

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> x = {x} 
> y = {a}*x
> y + 2
> x = {b}*y
> z = {b}*y
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