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a)

\n

x is a vector holding the sequence of numbers between $\\var{a}$ and $\\var{a+c-1}$, inclusive, i.e. {join(list(a..a+c-1),', ')}.

\n

length gives the number of elements in a vector. There are $\\var{c}$ elements in x.

\n

x+{d} adds $\\var{d}$ to each element of x, so the resulting vector has the same length.

\n

b)

\n

y is a single number, so length(y) is $1$.

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What is the value of $y$?

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{c}

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{{c}+{a}+{d}}

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{{c}+{d}}

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{{a}+{d}}

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{a}

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{c}

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1

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> x = seq({a},{c+a-1})
> y = length(x+{d})
> z = length(y)
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