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Solve linear equations with unknowns on one. Including brackets and fractions.
", "licence": "None specified"}, "statement": "Solve the following equations to find $x$:
", "advice": "\\[\\simplify{{a}x+{b} = {c}} \\]
\nThe first step is to isolate all the $x$-terms to one side of the equation.
\nTo do that we will {add} $\\var{abs(b)}$ onto both sides:
\n\\[\\var{a}x = \\simplify{{c-b}} \\]
\nNow we need to divide both sides by the coefficient of $x$, to leave just one $x$.
\nDividing both sides by $\\var{a}$,
\n\\[ x = {\\simplify{({c}-{b})/{a}}} \\]
\n\n \\[ \\frac{\\simplify{{d}x + {f}}}{\\var{g}} = \\var{h} \\]
The first step is to rearrange by removing the fraction on the left. To do this we mulitply both sides by $\\var{g}$.
\\[ \\begin{split} \\frac{\\simplify{{d}x + {f}}}{\\var{g}} \\times \\var{g} &= \\var{h} \\times \\var{g} \\\\\\\\ \\simplify{{d}x + {f}} &= \\var{h*g} \\end{split} \\]
Next we isolate all the $x$-terms onto one side of the equation.
To do that we will {add2} $\\var{abs(f)}$ on both sides:
\\[ \\begin{split} \\var{d}x &= \\simplify[]{{h*g}-{f}} \\\\ &= \\simplify[]{{h*g-f}} \\end{split}\\]
Finally we need to divide both sides by the coefficient of $x$, to leave just one $x$.
Dividing both sides by $\\var{d}$,
\\[x = \\simplify[fractionNumbers]{{(h*g-f)/d}} \\]
\\[ \\simplify{{b}({c}x+{g})} = \\var{d} \\]
\nEven though this looks different, this is quite similar to part b). We just have a multiplication rather than a division to deal with as the first step.
Rearrange to remove the multiplication on the left. To do this we divide both sides by $\\var{b}$:
\\[ \\begin{split} \\frac{\\simplify{{b}({c}x+{g})}}{ \\var{b}} &= \\frac{\\var{d}}{\\var{b}} \\\\ \\\\ \\simplify{{c}x+{g}} &= \\simplify[fractionNumbers]{{d/b}} \\end{split} \\]
Next we isolate all the $x$-terms onto one side of the equation.
To do that we will {add3} $\\var{abs(g)}$ on both sides:
\\[ \\begin {split} \\simplify{{c}x + {g}} \\var{add3sym} \\var{abs(g)} &= \\simplify[fractionNumbers]{{d/b}} \\var{add3sym} \\var{abs(g)} \\\\ \\var{c}x &= \\simplify[fractionNumbers]{{d/b-g}} \\end{split} \\]
Finally we need to divide both sides by the coefficient of $x$, to leave just one $x$
Dividing both sides by $\\var{c}$:
\\[ x = \\simplify[fractionNumbers]{{(d/b-g)/c}} \\]
$\\simplify{{a}x+{b} = {c}}$
\n\n$x=$ [[0]]
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\n\n$x=$ [[0]]
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\n\n$x=$ [[0]]
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