// Numbas version: exam_results_page_options {"name": "Ableitung von Exponentialfunktionen mit linearen Exponenten", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "Ableitung von Exponentialfunktionen mit linearen Exponenten", "tags": [], "metadata": {"description": "
Es werden grundlegenden Ableitungsregeln geübt.
\nDie Reihenfolge der Summanden ist auch randomisiert.
", "licence": "Creative Commons Attribution-ShareAlike 4.0 International"}, "statement": "Geben Sie die Ableitung f'(x) von f(x) an.
", "advice": "\nIn dieser Aufgabe
$ f(x) = \\simplify[std,!otherNumbers,!noLeadingMinus]{
{z[2]}*{c}e^({b[1]}*x+{b[0]}) + {a[1]}x^{n[1]} +
{z[1]}*{c}e^({b[1]}*x+{b[0]}) + {a[0]}x^{n[0]} +
{z[0]}*{c}e^({b[1]}*x+{b[0]}) }$
sind die einzelnen Ableitungen:
\\[ g(x) = \\simplify[std]{{a[1]}x ^ {n[1]}} \\Rightarrow g'(x) = \\var[fractionNumbers]{a[1]} \\cdot \\var{n[1]}x ^ \\var{n[1]-1} = \\simplify[std]{ {{a[1]}*{n[1]}}x ^ {n[1]-1} } \\]
\n\\[ g(x) = \\simplify[std]{{a[0]}x ^ {n[0]}} \\Rightarrow g'(x) = \\var[fractionNumbers]{a[0]} \\cdot \\var{n[0]}x ^ \\var{n[0]-1} = \\simplify[std]{ {{a[0]}*{n[0]}}x ^ {n[0]-1} } \\]
\n\\[ g(x) = \\simplify[std,!noLeadingMinus]{{c}e^({b[1]}*x+{b[0]}) } \\Rightarrow
g'(x) = (\\var[fractionNumbers]{c}) \\cdot (\\var{b[1]}) \\cdot \\simplify[std,!noLeadingMinus]{e^({b[1]}*x+{b[0]}) } =
\\simplify[std,!noLeadingMinus]{{c}*{b[1]}*e^({b[1]}*x+{b[0]}) } \\]
Also ist die Ableitung von $f$ :
$ f(x) = \\simplify[std,!otherNumbers,!noLeadingMinus]{
{c}*{b[1]}e^({b[1]}*x+{b[0]}) + {{a[1]}*{n[1]}}x ^ {n[1]-1} + {{a[0]}*{n[0]}}x ^ {n[0]-1} }$
Grad des Polynoms
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", "templateType": "anything", "can_override": false}, "c": {"name": "c", "group": "Ungrouped variables", "definition": "random([-1,1])*random(1..6)/random(1..6)", "description": "Koeffizient der Exponentialfunktion.
", "templateType": "anything", "can_override": false}, "b": {"name": "b", "group": "Ungrouped variables", "definition": "[random(-1 .. 1), random([-4,-3,-2,-1,1,2,3,4])]", "description": "Koeffizienten des linearen Exponenten
", "templateType": "anything", "can_override": false}, "z": {"name": "z", "group": "Ungrouped variables", "definition": "shuffle([1,0,0])", "description": "Position der e-Funktion in der Summe
", "templateType": "anything", "can_override": false}}, "variablesTest": {"condition": "", "maxRuns": 100}, "ungrouped_variables": ["n", "a", "c", "b", "z"], "variable_groups": [], "functions": {}, "preamble": {"js": "", "css": ""}, "parts": [{"type": "gapfill", "useCustomName": false, "customName": "", "marks": 0, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "prompt": "$ f(x) = \\simplify[std,!otherNumbers,!noLeadingMinus]{
{z[2]}*{c}e^({b[1]}*x+{b[0]}) + {a[1]}x^{n[1]} +
{z[1]}*{c}e^({b[1]}*x+{b[0]}) + {a[0]}x^{n[0]} +
{z[0]}*{c}e^({b[1]}*x+{b[0]}) }$
$\\displaystyle f'(x)=\\;$[[0]]
\n\nBitte beachten:
\nDie Ableitung einer Potenzfunktionen wird gebildet mit
\n\\[ f(x) = x^n \\Rightarrow f'(x) = n \\cdot x^{n-1} \\]
\nDie Ableitung einer Exponentialfunktion erfolgt mit die Kettenregel
\n\\[ f(x) = e^{kx+b} \\Rightarrow f'(x) = k \\cdot e^{kx+b} \\]
\nMit der Faktorregel
\n\\[ f(x) = a \\cdot g(x) \\Rightarrow f'(x) = a \\cdot g'(x) \\]
\nund der Summenregel
\n\\[ f(x) = g(x) + h(x) \\Rightarrow f'(x) = g'(x) + h'(x)\\]
\nkönnen Linearkombinationen von Funktionen abgeleitet werden.
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