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La $R=\\{\\var{a},\\var{b},\\var{c},\\var{d}\\}$ og $S=\\{\\var{b},\\var{c},\\var{d},\\var{f}\\}$.

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Oppgave a) $R\\cap S$: Her leses symbolet $\\cap$ som snitt, det er altså snakk bare det som ligger i begge mengdene. Dersom noe ligger i bare en av mengdene skal det altså ikke tas med.

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$R=\\{\\var{a},\\var{b},\\var{c},\\var{d}\\}$

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$S=\\{\\var{b},\\var{c},\\var{d},\\var{f}\\}$

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$R\\cap S=\\{\\var{b},\\var{c}\\}$

\n

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Oppgave b) $R\\cup S$:Husk at du kan tenke på $\\cup$ som addisjon. Vi ønsker å legge sammen alle elementene i $R$ og $S$. NB:husk at i en mengde er alle elementene unike så vi skriver ikke ett element mer enn èn gang.

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$R=\\{\\var{a},\\var{b},\\var{c},\\var{d}\\}$

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$S=\\{\\var{b},\\var{c},\\var{d},\\var{f}\\}$

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$R\\cup S=\\{\\var{a},\\var{b},\\var{c},\\var{d},\\var{f}\\}$

\n

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Oppgave c) $R\\setminus S$: Her leses $\\setminus$ som komplimentet til. Dette kan en litt feilaktig tenke på som subtraksjon eller minus. Vi ønsker med andre ord alt som ligger i $R$ men ikke i $S$:

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$R=\\{\\var{a},\\var{b},\\var{c},\\var{d}\\}$

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$S=\\{\\var{b},\\var{c},\\var{d},\\var{f}\\}$

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$R\\setminus S=\\{\\var{a}\\}$

\n

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Oppgave d)  $S\\setminus R$: Her leses $\\setminus$ som komplimentet til. Dette kan en litt feilaktig tenke på som subtraksjon eller minus. Vi ønsker med andre ord alt som ligger i $S$ men ikke i $R$:

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$R=\\{\\var{a},\\var{b},\\var{c},\\var{d}\\}$

\n

$S=\\{\\var{b},\\var{c},\\var{d},\\var{f}\\}$

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$S\\setminus R=\\{\\var{f}\\}$

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Finn $R\\cap S=\\{$[[0]],[[1]],[[2]]$\\}$

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Finn $R\\cup S=\\{$[[0]],[[1]],[[2]],[[3]],[[4]]$\\}$

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Finn $R \\setminus S=\\{$[[0]]$\\}$

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Finn $S\\setminus R=\\{$[[0]]$\\}$

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