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Hver $\\mathrm{cm}^2$ av Jordens overflate bærer en luftsøyle med masse 1 kg. Jordens overflate er $5,1\\cdot 10^8\\ \\mathrm{km}^2$.

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a) En metode er å regne om $5,1\\cdot 10^8\\ \\mathrm{km}$ til $\\mathrm{cm}^2$. Siden $1 \\mathrm{km}=10^3\\ \\mathrm{m}=10^5 \\mathrm{cm}$ får vi $5,1\\cdot 10^8\\ \\mathrm{km}^2=5,1\\cdot 10^8\\cdot(10^5\\ \\mathrm{cm})^2=5,1\\cdot 10^{8+5\\cdot 2}\\ \\mathrm{cm}^2=5,1\\cdot 10^{18}\\ \\mathrm{cm}^2$

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Atmosfæren sin masse er altså ca  $5,1\\cdot 10^{18}$ kg

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b) Nå trenger vi å regne ut 22% av svaret fra oppgave a). Siden% betyr hundrededdel så får vi

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$5,1\\cdot 10^{18}\\cdot0,22\\ \\mathrm{kg}=1,122\\cdot 10^{18}$ kg

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Finn atmosfærens masse i kg

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22% av atmosærens masse er oksygen. Finn massen av oksygenet i atmosfæren.

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